Find the 90% confidence interval for the mean number of pieces of junk mail received per week in the US. A random sample of 250 homes produced a mean of 36.45 pieces of mail. Assume the population standard deviation is 3.65 pieces. Interpret your answer. Part A - Fill out the pieces of the formula: ± times by Square root of Part B - To two decimal places, the interval is ( Part C-We are confident the population. pieces of junk mail. divided ) Make sure this is small value first. is between and

MATLAB: An Introduction with Applications
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### QUESTION 9

**Task:**
Find the 90% confidence interval for the mean number of pieces of junk mail received per week in the US. A random sample of 250 homes produced a mean of 36.45 pieces of mail. Assume the population standard deviation is 3.65 pieces. Interpret your answer.

**Part A:**
Fill out the pieces of the formula:

\[ \text{[Blank]} \pm \text{[Blank]} \times \text{[Blank]} \div \text{by square root of} \]

**Part B:**
To two decimal places, the interval is:

\[ (\text{[Blank]}, \text{[Blank]}) \]

Make sure this is the small value first.

**Part C:**
We are:

\[ \text{[Blank]} \]

confident the population:

\[ \text{[Blank]} \]

is between

\[ \text{[Blank]} \]

and

\[ \text{[Blank]} \]

pieces of junk mail.
Transcribed Image Text:### QUESTION 9 **Task:** Find the 90% confidence interval for the mean number of pieces of junk mail received per week in the US. A random sample of 250 homes produced a mean of 36.45 pieces of mail. Assume the population standard deviation is 3.65 pieces. Interpret your answer. **Part A:** Fill out the pieces of the formula: \[ \text{[Blank]} \pm \text{[Blank]} \times \text{[Blank]} \div \text{by square root of} \] **Part B:** To two decimal places, the interval is: \[ (\text{[Blank]}, \text{[Blank]}) \] Make sure this is the small value first. **Part C:** We are: \[ \text{[Blank]} \] confident the population: \[ \text{[Blank]} \] is between \[ \text{[Blank]} \] and \[ \text{[Blank]} \] pieces of junk mail.
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