Find out the effectivelength factor (k) from thechart for the column inunbraced frame shown.Use beam; L=5m,h=600mm, b=300mm,Ig=5.4x10°mm4 andcolumn; L2=8m,section:400x400mm,Ig=2.133x10°mm4.O a.1.1O b. 2O c. 0.8O d. 0.58

The chart to determine the K value is shown below:

Find out the effective length factor (k) from the chart for the column in unbraced frame shown. Use beam; L1=5m, h=600mm, b3300mm, Ig=5.4x10°mm4 and column; L2=8m, section:400x400mm, Ig=2.133x10°mm4. O a. 1.1 O b.2 O c. 0.8 O d. 0.58

Find out the effective length factor (k) from the chart for the column in unbraced frame shown. Use beam; L1=5m, h=600mm, b3300mm, Ig=5.4x10°mm4 and column; L2=8m, section:400x400mm, Ig=2.133x10°mm4. O a. 1.1 O b.2 O c. 0.8 O d. 0.58

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Properties of materials

A property of a material describes its characteristics and distinguishes it from the others. The material properties are described it in terms of its hardness, color, appearances, and so on. The material properties generally depend on the type of material, or whether it is a metal or an alloy. There are different kinds of material properties such as mechanical properties, thermal properties, physical properties, and chemical properties. Chemical properties describe the material in terms of a chemical change. The mechanical properties come into existence when the material is acted upon by an external load. Thermal properties are associated with the temperature of the material and specific heat.

Question

Find out the effective
length factor (k) from the
chart for the column in
unbraced frame shown.
Use beam; L=5m,
h=600mm, b=300mm,
Ig=5.4x10°mm4 and
column; L2=8m,
section:400x400mm,
Ig=2.133x10°mm4.
O a.1.1
O b. 2
O c. 0.8
O d. 0.58

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