Find | grxn (in kilojoules) when 1.00 g of calcium oxide is reacted with 250 mL of water to form calcium hydroxide. The temperature of the water increases from 25.00 °C to 26.08 °C. Assume the density and heat capacity of the solution are the same as they are for water. Respond with the correct number of significant figures in scientific notation (Use E notation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 10°)
Find | grxn (in kilojoules) when 1.00 g of calcium oxide is reacted with 250 mL of water to form calcium hydroxide. The temperature of the water increases from 25.00 °C to 26.08 °C. Assume the density and heat capacity of the solution are the same as they are for water. Respond with the correct number of significant figures in scientific notation (Use E notation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 10°)
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
Transcribed Image Text:Find qrxn (in kilojoules) when 1.00 g of calcium oxide is reacted with 250 mL of water to form calcium hydroxide. The temperature
of the water increases from 25.00 °C to 26.08 °C. Assume the density and heat capacity of the solution are the same as they are for
water.
Respond with the correct number of significant figures in scientific notation (Use E notation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 105)
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Step 1
consider the given information,
mass of calcium oxide = 1.00g
volume of water = 250 ml
the change in temperature , ∆T = 26.06 ℃ - 25 ℃ = 1.08 ℃
Now, density of water at 25℃ is = 0.997 g/ml
and the heat capacity of water = 4.184 J/g°C
so, mass water = 250ml × 0.997 g/ml = 249.25 g
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