Find L(y) y" - y = 1 0st< 2 It+1 t2 2 y(0) = y'(0) = 0 °L (1) = + +] -2s e %3| s(s2-1) s2-1 -2s L (y) = T + 1 3e 8(s2-1) s3 (s+1) (s2-1)s2 -28 (3s+1) e L (y) = s2 +s4 3e-2s 3-2s L (y) = - - s2 s(s² –1)
Find L(y) y" - y = 1 0st< 2 It+1 t2 2 y(0) = y'(0) = 0 °L (1) = + +] -2s e %3| s(s2-1) s2-1 -2s L (y) = T + 1 3e 8(s2-1) s3 (s+1) (s2-1)s2 -28 (3s+1) e L (y) = s2 +s4 3e-2s 3-2s L (y) = - - s2 s(s² –1)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
47c
![Find L(y)
(1
y" - y =
t +1
0 <t< 2
t 2
y(0) = y'(0) = 0
L (1) = + +]
2s
e
s(s² –1)
L (4) = +
1
Зе
2s
%3D
s(s2-1)
s3 (s+1)
(s2 –1)s²
-2s (3s+1)
e
L (y)
s2+s4
3e-2s
3-2s
L (y)
us
s2
8(s² –1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F423035e8-5bab-47be-9b30-3ccc0deb20f0%2Fc8a15e87-3c7b-495d-a03e-61bf5dc60970%2F0wc55gc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find L(y)
(1
y" - y =
t +1
0 <t< 2
t 2
y(0) = y'(0) = 0
L (1) = + +]
2s
e
s(s² –1)
L (4) = +
1
Зе
2s
%3D
s(s2-1)
s3 (s+1)
(s2 –1)s²
-2s (3s+1)
e
L (y)
s2+s4
3e-2s
3-2s
L (y)
us
s2
8(s² –1)
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