Find Integral (cos(x) cos (2x) cos (5x) dx : considering cos (mx) cos (nx)= = (cos((m-n)x)+ cos ((min)x)]

Q: Find f. f'(t) 8 cos(t) + sec?(t), -7/2 <t < a/2, f(a/3) = 5 f(t) =

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Q: Let f(x) = 3 cos a - 2 tan a f'(x) = r() - C f'

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Q: Find f(x), where f'(x) = sin(x)+ cos(x) + 1 and f(r) = 2. %3D %3D

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Q: s¯¹(x + 1) − √√14 − 3x², find ƒ¹(x). If f(x) = 3x cos

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Q: cos(4x) cos(2x) sin(4x) sec(2x) 12. Verify: - sin(2x)

A: cos(2x ) =cos2(x)-sin2(x) = 2cos2(x)-1 =1-2sin2(x) sin(2x) = 2sin(x) cos(x)

Q: et ƒ(x) = 3x² cos(4x). ='(x) = −12x² sin(4x) + 6x cos(4x) (2) = 17.245 "(2) = =

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Q: Find F'(x), f"(x) and f'"(x) for f(x)=x$+cos(9x).

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Q: Find f f(0) = 2, f '(0) = 1 f "(0) sin 0 + cos 0, f(0)

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Q: Can you find f

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Q: Find f if f'(x) = 2 + cos(x), ƒ(0) = 10, ƒ(π/2) = 6. 2 f(x) = x² − cos(x) – (n - + - (x + 10 ) x +…

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Q: If f(x) = 7cos(x), what is f'(x) ?

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Q: Let f(x) = 6 sin ¹(x²). Then f'(x) equals 12x √1-x² 1 1- x4 6 /1-x² 12x cos−¹(x²) 12x √1 x4

A: The objective is to find the derivative of f(x).

Q: Find f. f "(0) = sin 0 + cos 0, f(0) = 1, f'(0) = 3

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Q: Let f (x)  =  (tan−1(x))2. Find f '( 1/3).

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Q: cos (x) J = g(x): x2

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Q: (a) [In(4) - 2e¹³] dx d b) dx d (c) [2²² - 1 (2²)] = 4e³x In(x [sec (12r) + tan-¹(2x)]

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Q: Find f. f "(x) = 9 + cos x, f(0) = -1, f(7t/2) = 0 f(x) =

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