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Find i and v, in the circuit of Fig. 7.15. Let i(0) = 5 A. Practice Problem 7.3 42 Answer: 5e4 V, -20e4 V. 12 2H 2v Figure 7.15 For Practice Prob. 7.3. The switch in the circuit of Fig. 7.16 has been closed for a long time. At t 0, the switch is opened. Calculate i(t) for t> 0. Example 7.4 t=0 2Ω 4Ω Solution: When t< 0, the switch is closed, and the inductor acts as a short circuit to de. The 16-2 resistor is short-circuited; the resulting circuit is shown in Fig. 7.17(a). To get i, in Fig. 7.17(a), we combine the 4-2 and 12-2 resistors in parallel to get i(1) 40 V 12 2 16 2 2 H ww

Find i and v, in the circuit of Fig. 7.15. Let i(0) = 5 A. Practice Problem 7.3 42 Answer: 5e4 V, -20e4 V. 12 2H 2v Figure 7.15 For Practice Prob. 7.3. The switch in the circuit of Fig. 7.16 has been closed for a long time. At t 0, the switch is opened. Calculate i(t) for t> 0. Example 7.4 t=0 2Ω 4Ω Solution: When t< 0, the switch is closed, and the inductor acts as a short circuit to de. The 16-2 resistor is short-circuited; the resulting circuit is shown in Fig. 7.17(a). To get i, in Fig. 7.17(a), we combine the 4-2 and 12-2 resistors in parallel to get i(1) 40 V 12 2 16 2 2 H ww

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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luan (D Page view A Read aloud V Draw 7.3 The Source-Free RL Circuit 263 Since the inductor and the 2-2 resistor are in parallel, (1) = -1.6667e-(2/3)t A. t > 0 %3D Find i and v, in the circuit of Fig. 7.15. Let i(0) = 5 A. Practice Problem 7.3 4Ω Answer: 5e"V,-20e4 V. 12 2 H .4Ω 2v Figure 7.15 For Practice Prob. 7.3. The switch in the circuit of Fig. 7.16 has been closed for a long time. At t = 0, the switch is opened. Calculate i(t) for t > 0. Example 7.4 t = 0 2Ω 4Ω Solution: When t< 0, the switch is closed, and the inductor acts as a short circuit to dc. The 16-2 resistor is short-circuited; the resulting circuit is shown in Fig. 7.17(a). To get i, in Fig. 7.17(a), we combine the 4-2 and 12-2 resistors in parallel to get i(1) 40 V I 12 2 E 162 2 H ll
Transcribed Image Text:luan (D Page view A Read aloud V Draw 7.3 The Source-Free RL Circuit 263 Since the inductor and the 2-2 resistor are in parallel, (1) = -1.6667e-(2/3)t A. t > 0 %3D Find i and v, in the circuit of Fig. 7.15. Let i(0) = 5 A. Practice Problem 7.3 4Ω Answer: 5e"V,-20e4 V. 12 2 H .4Ω 2v Figure 7.15 For Practice Prob. 7.3. The switch in the circuit of Fig. 7.16 has been closed for a long time. At t = 0, the switch is opened. Calculate i(t) for t > 0. Example 7.4 t = 0 2Ω 4Ω Solution: When t< 0, the switch is closed, and the inductor acts as a short circuit to dc. The 16-2 resistor is short-circuited; the resulting circuit is shown in Fig. 7.17(a). To get i, in Fig. 7.17(a), we combine the 4-2 and 12-2 resistors in parallel to get i(1) 40 V I 12 2 E 162 2 H ll
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