Find f'(a). 2t + 12 f(t) = t + 9 f'(a) =

Q: Find f. f ''(x) = 20x3 + 12x2 + 10,    f(0) = 4,    f(1) = 2

A:

Q: Find f. f"(x)  =-2  +12 x -12 x2   , f(0)   = 4 ,f'(0)  =12

A: Given ,f''x=-2+12x-12x2f0=4f'0=12

Q: Find F'(8) and F''(8).

A: We need to use second fundamental theorem of calculus with f(t)= sqrt(t^2+17) and a=8

Q: -4 Find f'(x) when f(x) = -

A: We will solve the problem

Q: 3 find f'(x). x2 7 If f(x) = 7+ -+

A:

Q: rsin(r2) Let g(x) 1 and f(x) g(t) dt. Find f' (2). xª + 1

A: From the given information we can apply the fundamental theorem of calculus.

Q: Find f. f ''(t) = 9/sqt t,    f(4) = 29,    f '(4) = 9

A:

Q: Find f '(a) f(t)6t12 t 7

A: The given function is

Q: Let f(r) = 2e + 7x + 6, then f(8) = %3D

A:

Q: Find f. f ''(x) = 4 − 18x,    f(0) = 8,    f(2) = 8

A:

Q: On which interval(s) is the function h(t) = (−t^3) + 3(t^2) + 24t − 11 decreasing?

A:

Q: Find f' (x) for ƒ (x) = 8x° – 3e".

A: Given : fx = 8xe - 3ex

Q: differentiate y = (x - 1)/(x + 1)

A: Given function: y=x-1x+1 Differentiate the above function w.r.t 'x' dydx=ddxx-1x+1

Q: Find f. f ''(x) = 4 + 6x + 24x2,    f(0) = 5,    f (1) = 14

A: To find out the function f whose double derivative and some initial conditions are given.

Q: Find f. f ''(t) = 9/square root of t,    f(4) = 26,    f '(4) = 13

A:

Q: Find f. f"(x) = -2 + 30x – 12x2, f(0) = 8, f'(0) = 16

A:

Q: B. f(x)=ln 5x² sin x (x+7)

A: We have to find the f'(x).

Q: Find f'(t) if f(t)= -2t² - 8t+7. f'(t) =

A: We need to find out the derivative of the given function.

Q: Find f '(a) f(t) = (8t + 34)/(t + 9) f '(a) =

A:

Q: Find f. f'(x)  = 5x4 - 3x2   + 4    , f(-1)  =2

A: we have to find the value of 'f' f'(x)  = 5x4  -3x2   + 4    , f(-1)  =2

Q: If f(x) = (3 +3) -, find f'(x). %3D Find f'(5).

A: Given: fx=3x+3-2 f'x=-23x+3-3×3       =-63x+3-3 Therefore, f'x=-63x+3-3 .

Q: Find f. f ''(x) = 20x3 + 12x2 + 4, f(0) = 5, f(1) = 2

A: The objective is to find f .

Q: ƒ(x) = 8x¹³¹(x), find ƒ'(3).

A: Given query is to find indicated derivative.