Find f'(t) if f(t)= -2t² - 8t+7. f'(t) =

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem: Finding the Derivative**

Determine \( f'(t) \) if \( f(t) = -2t^2 - 8t + 7 \).

---

**Solution:**

To find the derivative \( f'(t) \), apply the power rule to each term of \( f(t) \).

1. **Derivative of \(-2t^2\):**
   - The derivative of \( t^n \) is \( n \cdot t^{n-1} \).
   - Apply this to \(-2t^2\): 
     \[
     -2 \cdot 2t^{2-1} = -4t
     \]

2. **Derivative of \(-8t\):**
   - The derivative of \( t \) is 1.
   - Apply to \(-8t\):
     \[
     -8 \cdot 1 = -8
     \]

3. **Derivative of \(7\):**
   - The derivative of a constant is 0.

**Result:**
Combine the derivatives:
\[
f'(t) = -4t - 8
\] 

The derivative \( f'(t) = -4t - 8 \) represents the slope of the tangent line to the curve \( f(t) \) at any point \( t \).
Transcribed Image Text:**Problem: Finding the Derivative** Determine \( f'(t) \) if \( f(t) = -2t^2 - 8t + 7 \). --- **Solution:** To find the derivative \( f'(t) \), apply the power rule to each term of \( f(t) \). 1. **Derivative of \(-2t^2\):** - The derivative of \( t^n \) is \( n \cdot t^{n-1} \). - Apply this to \(-2t^2\): \[ -2 \cdot 2t^{2-1} = -4t \] 2. **Derivative of \(-8t\):** - The derivative of \( t \) is 1. - Apply to \(-8t\): \[ -8 \cdot 1 = -8 \] 3. **Derivative of \(7\):** - The derivative of a constant is 0. **Result:** Combine the derivatives: \[ f'(t) = -4t - 8 \] The derivative \( f'(t) = -4t - 8 \) represents the slope of the tangent line to the curve \( f(t) \) at any point \( t \).
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