I need help solving. I left my books overseas. NameLESSON5-4ReteachThe Triangle Midsegment Theorem continuedTheoremTriangle Midsegment TheoremA midsegment of a triangle is parallel toa side of the triangle, and its length ishalf the length of that side.HJ= AC A Midsegment Thm.2You can use the Triangle Midsegment Theorem tofind various measures in AABC.HJ = (12) Substitute 12 for AC:=(12)HJ=6Simplify.JK ==AB A Midsegment Thm.214= AB Substitute 4 for JK.2¹8 = ABDateSimplify.Find each measure..8. VX=9. HJ=10. m/VXJ =11. XJ=Find each measure.12. ST=13. DE=14. m/DES=15. m/RCD=NGiven: PQ is a midsegment of ALMN.Conclusion: PQ || LN, PQ =LN2HJ || ACm/BCAAHm/BCA = 35°B=mZBJH=DExample41235°K27Midsegment Thm.ClassCorr. Thm.Substitute 35° for mZBJH.48°H92°E36R44Original content Copyright by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor.5-31Holt Geometry

Answered: Find each measure. .8. VX= 9. HJ= 10.…

Find each measure. .8. VX= 9. HJ= 10. m/VXJ= 11. XJ= Find each measure. 12. ST= 13. DE= 14. m/DES= 15. m/RCD= 46 W 27 H D 48° H 92° E 36 R H C 35 for mZBJH. 44

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

ChapterP: Preliminary Concepts

SectionP.CT: Test

Problem 1CT

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Question

I need help solving. I left my books overseas.

Name
LESSON
5-4
Reteach
The Triangle Midsegment Theorem continued
Theorem
Triangle Midsegment Theorem
A midsegment of a triangle is parallel to
a side of the triangle, and its length is
half the length of that side.
HJ= AC A Midsegment Thm.
2
You can use the Triangle Midsegment Theorem to
find various measures in AABC.
HJ = (12) Substitute 12 for AC:
=(12)
HJ=6
Simplify.
JK ==AB A Midsegment Thm.
2
1
4= AB Substitute 4 for JK.
2
¹8 = AB
Date
Simplify.
Find each measure.
.8. VX=
9. HJ=
10. m/VXJ =
11. XJ=
Find each measure.
12. ST=
13. DE=
14. m/DES=
15. m/RCD=
N
Given: PQ is a midsegment of ALMN.
Conclusion: PQ || LN, PQ =
LN
2
HJ || AC
m/BCA
A
H
m/BCA = 35°
B
=mZBJH
=
D
Example
4
12
35°
K
27
Midsegment Thm.
Class
Corr. Thm.
Substitute 35° for mZBJH.
48°
H
92°
E
36
R
44
Original content Copyright by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor.
5-31
Holt Geometry

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Concept:

According to the midsegment theorem, every line segment connecting any two triangle sides' midpoints is parallel to and comprises half of the third side.
Parallel Lines are any Two or more Lines that all lie in the Same Plane and never Cross one another. Both of them have the same slope and are equally spaced apart.

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