### Problem Statement: Calculate the Coefficient of Performance (COP) of a reversible heat pump operating between temperatures 20°C and 200°C.### Explanation:The Coefficient of Performance (COP) of a heat pump is a measure of its efficiency, defined as the ratio of the heat delivered to the work input. For a reversible heat pump, the COP can be calculated using the temperatures of the hot and cold reservoirs.Given:- Temperature of the cold reservoir (T_cold) = 20°C = 293 K - Temperature of the hot reservoir (T_hot) = 200°C = 473 K The formula for COP of a heat pump is:\[\text{COP} = \frac{T_{\text{hot}}}{T_{\text{hot}} - T_{\text{cold}}}\]### Calculation:Substitute the given temperatures (in Kelvin) into the formula:\[\text{COP} = \frac{473}{473 - 293} = \frac{473}{180} \approx 2.63\]### Conclusion:The Coefficient of Performance (COP) of the reversible heat pump operating between temperatures 20°C and 200°C is approximately 2.63.

Given, Temperature of hot reservoir = TH = 200 oC = 473 K, Temperature of cool reservoir = TL = 20…

Answered: Find COP of a reversible heat pump…

Engineering

Mechanical Engineering

Find COP of a reversible heat pump operating between temperatures 20 and 200 °c

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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