I was wondering how did I get this wrong. I found the derivative of the equation and plug in the point so this should be right. Can somebody tell me how to solve it? Find an equation of the tangent line to the curve $ y = \frac{5e^x}{x^2 + 1} $ at the point $(0, 5)$.\[ y = 5x - 5 \] ❌---The image consists of a mathematical problem where a tangent line to a curve needs to be found. The given curve is expressed as $ y = \frac{5e^x}{x^2 + 1} $ and the point of tangency is $(0, 5)$. Below the problem, there is an incorrect solution boxed, which suggests that the equation $ y = 5x - 5 $ is not the correct tangent line equation as indicated by a red cross.

Given, y =5exx2+1 and point (0,5)

Answered: Find an equation of the tangent line to…

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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I was wondering how did I get this wrong. I found the derivative of the equation and plug in the point so this should be right. Can somebody tell me how to solve it?

Find an equation of the tangent line to the curve $ y = \frac{5e^x}{x^2 + 1} $ at the point $(0, 5)$.

\[ y = 5x - 5 \] ❌

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The image consists of a mathematical problem where a tangent line to a curve needs to be found.

The given curve is expressed as $ y = \frac{5e^x}{x^2 + 1} $ and the point of tangency is $(0, 5)$. Below the problem, there is an incorrect solution boxed, which suggests that the equation $ y = 5x - 5 $ is not the correct tangent line equation as indicated by a red cross.

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$G i v e n, y = \frac{5 e^{x}}{x^{2} + 1} a n d p o i n t (0, 5)$

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