Find an equation of the sphere that passes through the origin and whose center is (6, – 6, 3). OA. (x + 6)* + (y - 6)* + (z - 3)' = 9 OB. (x-6)? + (y+6)* + (z-3)² = 9 OC. °(x + 6)* + (y-6) + (z +3) = 9 -(y-6)* + (z+3)² = 9 OD 2 +y? +z? = 9 OE. (x - 6)* + (y+6)* + (z-3)? = 81

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question 2
Find an equation of the sphere that passes through the origin and whose center is (6, – 6, 3).
OA.
2
*(x + 6)? + (y -6)+ (z-3) = 9
OB.
(x - 6)' + (y +6)+ (z– 3) = 9
OC.
(*+6)* + (y-6)* + (2+ 3)* = 9
O D.? + y? +z? = 9
OE (x- 6)? + (y+6) + (z-3)° = 81
Transcribed Image Text:Question 2 Find an equation of the sphere that passes through the origin and whose center is (6, – 6, 3). OA. 2 *(x + 6)? + (y -6)+ (z-3) = 9 OB. (x - 6)' + (y +6)+ (z– 3) = 9 OC. (*+6)* + (y-6)* + (2+ 3)* = 9 O D.? + y? +z? = 9 OE (x- 6)? + (y+6) + (z-3)° = 81
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