Identify the focus and directrix of the parabola: y = -4(x - 2)² - 3. f: (1, -4), d: y = 2 f: (2, -4), d: y = -1 t. (2-3-1). d y = -215 f: d: 16 15 °r. (2-25). d.y=-31 15 f: d: == 16 16
Identify the focus and directrix of the parabola: y = -4(x - 2)² - 3. f: (1, -4), d: y = 2 f: (2, -4), d: y = -1 t. (2-3-1). d y = -215 f: d: 16 15 °r. (2-25). d.y=-31 15 f: d: == 16 16
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:Identify the focus and directrix of the parabola: y = -4(x - 2)² - 3.
Of: (1, -4), d: y = 2
f: (2, -4), d: y = -1
Of: (2-3-1). d y = -2 15
d.
d:
16
15
Pt: (2-216). dy--3 1/
f:
d:
16
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