Find an equation of the plane containing the points (0, 1, 0), (2, 1, 1) and (-1,3,0). O A. The three given points are collinear. They do not span a plane. О В. 2х + у — 42 + 1 — 0 С. 2х + у — 423D 1 O D. Зх +у — 62 — 1 O E. 2x + y+ 4z = 1

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A: As per our guidelines I am solving only first problem please repost other question.  9. A' after AB…

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A: Solution

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