The equation of the plane that contains the three points (1, 2, 0), (1, 3, 1), and (3, 0, 4) is 6x +2y - 2z =11 а. b. 2x +3y+2z = 6 Зx+2у-z37 d. 2x +3y +2z = 13 3x +y- z =5 с. е.

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The equation of the plane that contains the three points (1, 2, 0), (1, 3, 1),
and (3, 0, 4) is
6x + 2y - 2z =11
b. 2х+3у +2z%36
3x +2y - z =7
d. 2x +3y +2z = 13
а.
С.
е.
Зx+у-z%35
a
O d
Transcribed Image Text:The equation of the plane that contains the three points (1, 2, 0), (1, 3, 1), and (3, 0, 4) is 6x + 2y - 2z =11 b. 2х+3у +2z%36 3x +2y - z =7 d. 2x +3y +2z = 13 а. С. е. Зx+у-z%35 a O d
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