Find all relative extrema and saddle points of the function. Use the Second Partials Test where applicable. (If an answer does not exist, enter DNE.) ه امر تمر ( - =G- x² + y2 )e! - x2 - y2 relative minima (x, y, z) = ( (smaller x-value) (x, y, z) = ( (larger x-value) (х, у, 2) 3( (smaller y-value) relative maxima (x, y, z) = ( | (larger y-value) saddle point (x, y, z) =

Q: Find the critical points of the functions f (x, y) = x² + 2y² − 4y + 2x, g (x, y) = x² — 12xy + y…

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A: Here, g'(x) = f(x), so, the horizontal tangent for g(x) occurs when f(x)=0, i.e., g'(x) =0. In open…

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Q: Suppose that f(x, y) = 4x² + 4y¹ then the minimum is -2xy

A: 1st we will find critical points  At critical point    fx ( partial differentiation  with respect to…

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A: Second derivative test is not applicable then we apply first derivative test.

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A: The Critical PointThe point is said to be critical point if The Second Derivative TestSuppose then…

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Q: Using linear approximation of f(x,y)=*+Y at (3,2), the value of f(2.94,1.94) estimated to be x-y

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A: Simple Linear Scaling:If f2(x) and f3(x) are linear functions that map the [0, L] interval to [a, b]…

Q: (x,y)= 2x3-6x+6xy2 Find the local maximum value(s), local minimum value(s), and saddle point(s)

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Q: Find the location of the maxima, minima, and saddle points of f(x,y), if any, given the partial…

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