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Normalize (z) = 3f2(x) +2f3(x). You can think of functions being 0 beyond the [0, L] interval, where L = 3, 2, 5.

Normalize (z) = 3f2(x) +2f3(x). You can think of functions being 0 beyond the [0, L] interval, where L = 3, 2, 5.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Normalize (r) = 3f₂(x) + 2f3(x). : You can think of functions being 0 beyond the [0, L] interval, where L = 3, 2, 5.
Transcribed Image Text:Normalize (r) = 3f₂(x) + 2f3(x). : You can think of functions being 0 beyond the [0, L] interval, where L = 3, 2, 5.
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