Find a vector equation of the line through (3,4,6) that is perpendicular to the lines r₁ (t)= (4-6t,5+7t,8-3t) and r₂(t)= (-6t,5+1,8-t). (x,y,z) = (..+ t (-4,12,36) (0, -14,8) (0, -13,35) (0,5,37)
Find a vector equation of the line through (3,4,6) that is perpendicular to the lines r₁ (t)= (4-6t,5+7t,8-3t) and r₂(t)= (-6t,5+1,8-t). (x,y,z) = (..+ t (-4,12,36) (0, -14,8) (0, -13,35) (0,5,37)
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter10: Analytic Geometry
Section10.6: The Three-dimensional Coordinate System
Problem 7E
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HW5 Q4
![Find a vector equation of the line through (3,4,6) that is perpendicular to the lines r₁ (t)= (4-6t,5+7t,8-3t) and r₂(t)= (-6t,5+1,8-t).
(x,y,z) = (..)+t
▼
(-4,12,36)
(0, -14,8)
(0, -13,35)
(0,5,37)
Search
O
O
→
L](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F43c6c60e-7312-49f6-8756-8967bc0098ca%2Fa15a4318-66f0-4bc5-b9e1-c6271e8593a2%2Fj25eki_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find a vector equation of the line through (3,4,6) that is perpendicular to the lines r₁ (t)= (4-6t,5+7t,8-3t) and r₂(t)= (-6t,5+1,8-t).
(x,y,z) = (..)+t
▼
(-4,12,36)
(0, -14,8)
(0, -13,35)
(0,5,37)
Search
O
O
→
L
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