each Cr.(6) Find a formula for ttie Biemann sum odividing [a,6] into n equal Subintervals and usingosteined bytthe rigut end (ii) left endpoinepoint(1) mi end point for each ci. Then take a limitpo(ii:) m.of these Sums n-> 0to calculate the grea underthe curve over L9,6].f(x)=2x²_32²Overr the interval [2,6].2)

Answered: Image /qna-images/answer/04e39fe5-41be-484f-8360-0f8812797117.jpg

Find a formula for the Biemann sum obteined by dividing Ca,6] into a equal subintervals and using the rigut end point lii) left endpoint (i:) mid end poine for each cie Then take a limit of tthese Sums n>oo to calculate the area under the curve over [a,b]. f(x)= 2x²-3x² Over the interval [2,6].'

Find a formula for the Biemann sum obteined by dividing Ca,6] into a equal subintervals and using the rigut end point lii) left endpoint (i:) mid end poine for each cie Then take a limit of tthese Sums n>oo to calculate the area under the curve over [a,b]. f(x)= 2x²-3x² Over the interval [2,6].'

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter7: Analytic Trigonometry

Section7.6: The Inverse Trigonometric Functions

Problem 74E

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Concept explainers

Riemann Sum

Riemann Sums is a special type of approximation of the area under a curve by dividing it into multiple simple shapes like rectangles or trapezoids and is used in integrals when finite sums are involved. Figuring out the area of a curve is complex hence this method makes it simple. Usually, we take the help of different integration methods for this purpose. This is one of the major parts of integral calculus.

Riemann Integral

Bernhard Riemann's integral was the first systematic description of the integral of a function on an interval in the branch of mathematics known as real analysis.

Question

each Cr.
(6) Find a formula for ttie Biemann sum o
dividing [a,6] into n equal Subintervals and using
osteined by
tthe rigut end (ii) left endpoine
point
(1) mi end point for each ci. Then take a limit
po
(ii:) m.
of these Sums n-> 0to calculate the grea under
the curve over L9,6].
f(x)=2x²_32²
Over
r the interval [2,6].
2)

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