Find a Basis for Span = {(1,1,1), (- 1,1,– 1), (2,4,2), (1,1,3)) a. '((1,1,1),(-1,1,– 1),(2,4,2))} b. (1,1,1),(2,4,2),(1,1,3),(-1,1,– 1)) {(1,1,1),(-1,1,– 1),(1,1,3)} d. ((1,0,0),(– 1,1,0),(1,0,1),(0,1,1/2)} с.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Find a Basis for Span= ((1,1,1), (- 1,1,- 1), (2,4,2), (1,1,3)}
%3D
a. '((1,1,1),(-1,1, – 1),(2,4,2)}
b. ((1,1,1),(2,4,2),(1,1,3),(-1,1, – 1)}
c. (1,1,1),(-1,1, – 1),(1,1,3)}
d. ((1,0,0),(–1,1,0),(1,0,1),(0,1,1/2)}
Transcribed Image Text:Find a Basis for Span= ((1,1,1), (- 1,1,- 1), (2,4,2), (1,1,3)} %3D a. '((1,1,1),(-1,1, – 1),(2,4,2)} b. ((1,1,1),(2,4,2),(1,1,3),(-1,1, – 1)} c. (1,1,1),(-1,1, – 1),(1,1,3)} d. ((1,0,0),(–1,1,0),(1,0,1),(0,1,1/2)}
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