Find 75307 mod 735 using the techniques described in Example 8.4.4 and Example 8.4.5. First compute the following. 751 mod 735 = 752 mod 735 754 mod 735 = 758 mod 735 = 7516 mod 735 = 7532 mod 735 = 7564 mod 735 = 75128 mod 735 = 75256 mod 735 = Since 307 = 256 + 32 + 16 + 2 + 1, 75307 mod 735 = 75256. 7532. 75 752 . 75')mod 735 *((75256 (75256, mod 735) · (7532 mod 735) · (75– mod 735) · (752 mod 735) · (751 mod 735) )mod 735
Find 75307 mod 735 using the techniques described in Example 8.4.4 and Example 8.4.5. First compute the following. 751 mod 735 = 752 mod 735 754 mod 735 = 758 mod 735 = 7516 mod 735 = 7532 mod 735 = 7564 mod 735 = 75128 mod 735 = 75256 mod 735 = Since 307 = 256 + 32 + 16 + 2 + 1, 75307 mod 735 = 75256. 7532. 75 752 . 75')mod 735 *((75256 (75256, mod 735) · (7532 mod 735) · (75– mod 735) · (752 mod 735) · (751 mod 735) )mod 735
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:Find 75307 mod 735 using the techniques described in Example 8.4.4 and Example 8.4.5.
First compute the following.
751 mod 735 =
752 mod 735
754 mod 735 =
758 mod 735 =
7516 mod 735 =
7532 mod 735 =
7564 mod 735 =
75128 mod 735 =
75256 mod 735 =
Since 307 = 256 + 32 + 16 + 2 + 1,
75307 mod 735 =
75256. 7532. 75
752 . 75')mod 735
*((75256
(75256,
mod 735) · (7532 mod 735) · (75–
mod 735) · (752 mod 735) · (751 mod 735) )mod 735
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