Find 75307 mod 735 using the techniques described in Example 8.4.4 and Example 8.4.5. First compute the following. 751 mod 735 = 752 mod 735 754 mod 735 = 758 mod 735 = 7516 mod 735 = 7532 mod 735 = 7564 mod 735 = 75128 mod 735 = 75256 mod 735 = Since 307 = 256 + 32 + 16 + 2 + 1, 75307 mod 735 = 75256. 7532. 75 752 . 75')mod 735 *((75256 (75256, mod 735) · (7532 mod 735) · (75– mod 735) · (752 mod 735) · (751 mod 735) )mod 735

Find 75307 mod 735 using the techniques described in Example 8.4.4 and Example 8.4.5. First compute the following. 751 mod 735 = 752 mod 735 754 mod 735 = 758 mod 735 = 7516 mod 735 = 7532 mod 735 = 7564 mod 735 = 75128 mod 735 = 75256 mod 735 = Since 307 = 256 + 32 + 16 + 2 + 1, 75307 mod 735 = 75256. 7532. 75 752 . 75')mod 735 *((75256 (75256, mod 735) · (7532 mod 735) · (75– mod 735) · (752 mod 735) · (751 mod 735) )mod 735

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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