Find 0, if 0° <0 < 360° and 1 and 0 in III. 2 cos 0 =
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Question
![**Problem Statement:**
Find \( \theta \), if \( 0^\circ < \theta < 360^\circ \) and
\[ \cos \theta = -\frac{1}{2} \]
and \( \theta \) is in Quadrant III.
\[ \theta = \]
**Explanation:**
The problem asks to find the angle \( \theta \) given that it is between 0° and 360°, the cosine of \( \theta \) is \(-\frac{1}{2}\), and \( \theta \) is in the third quadrant of the unit circle. Quadrant III refers to the range of angles between 180° and 270°, where the cosine value is negative.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F42bd253a-231b-4c16-baac-6c405dc75416%2F51bbfb51-634c-4855-834d-ee2ab74afa4e%2Folzfa7a_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Find \( \theta \), if \( 0^\circ < \theta < 360^\circ \) and
\[ \cos \theta = -\frac{1}{2} \]
and \( \theta \) is in Quadrant III.
\[ \theta = \]
**Explanation:**
The problem asks to find the angle \( \theta \) given that it is between 0° and 360°, the cosine of \( \theta \) is \(-\frac{1}{2}\), and \( \theta \) is in the third quadrant of the unit circle. Quadrant III refers to the range of angles between 180° and 270°, where the cosine value is negative.
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