If sin A = with A in QII, find Cos 9 cos Cos COS Cos Cos 스2

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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### Problem Statement

Given: 

If \( \sin A = -\frac{4}{5} \) with \( A \) in the third quadrant (QIII), find \( \cos \frac{A}{2} \).

### Options

- \( \cos \frac{A}{2} = -\frac{9}{\sqrt{10}} \)
- \( \cos \frac{A}{2} = -\frac{1}{\sqrt{4}} \)
- \( \cos \frac{A}{2} = -\frac{1}{\sqrt{5}} \)
- \( \cos \frac{A}{2} = \frac{1}{\sqrt{9}} \)
- \( \cos \frac{A}{2} = \frac{1}{\sqrt{5}} \)

### Notes for Solving

To solve this problem, consider using the identity:

\[
\cos \frac{A}{2} = \pm \sqrt{\frac{1 + \cos A}{2}}
\]

Given that \( A \) is in the third quadrant, both sine and cosine are negative, thus helping determine the sign of the half-angle.
Transcribed Image Text:### Problem Statement Given: If \( \sin A = -\frac{4}{5} \) with \( A \) in the third quadrant (QIII), find \( \cos \frac{A}{2} \). ### Options - \( \cos \frac{A}{2} = -\frac{9}{\sqrt{10}} \) - \( \cos \frac{A}{2} = -\frac{1}{\sqrt{4}} \) - \( \cos \frac{A}{2} = -\frac{1}{\sqrt{5}} \) - \( \cos \frac{A}{2} = \frac{1}{\sqrt{9}} \) - \( \cos \frac{A}{2} = \frac{1}{\sqrt{5}} \) ### Notes for Solving To solve this problem, consider using the identity: \[ \cos \frac{A}{2} = \pm \sqrt{\frac{1 + \cos A}{2}} \] Given that \( A \) is in the third quadrant, both sine and cosine are negative, thus helping determine the sign of the half-angle.
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