Final positionkvA small block of mass m slides to the left on a frictionless,horizontal surface with speed v. Then, the block slides up amrough ramp that has an incline angle of 0. The coefficient ofRough surfaceInitial positionkinetic friction between the ramp and box is µ. TheVacceleration due to gravity is g.mFrictionless surfaceWhat is the height h of the block when its speed up the rampequals kv, where 0 < k < 1?h =

Name: Final positionkvA small block of mass m slides to the left on a frict
Uploaded: 2024-03-20T06:57:37.000Z
Channel: Bartleby
Description: Final positionkvA small block of mass m slides to the left on a frictionless,horizontal surface with speed v. Then, the block slides up amrough ramp that has an incline angle of 0. The coefficient ofRough surfaceInitial positionkinetic friction betw

Given: The speed of the block on the frictionless surface is v. The angle of inclination is θ. The…

Science

Physics

Final position A small block of mass m slides to the left on a frictionless, kv horizontal surface with speed v. Then, the block slides up a `Ax. rough ramp that has an incline angle of 0. The coefficient of Rough surface h kinetic friction between the ramp and box is u. The Initial position acceleration due to gravity is g. m Frictionless surface What is the height h of the block when its speed up the ramp equals kv, where 0 < k < 1? h =

Final position A small block of mass m slides to the left on a frictionless, kv horizontal surface with speed v. Then, the block slides up a `Ax. rough ramp that has an incline angle of 0. The coefficient of Rough surface h kinetic friction between the ramp and box is u. The Initial position acceleration due to gravity is g. m Frictionless surface What is the height h of the block when its speed up the ramp equals kv, where 0 < k < 1? h =

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A 0.170 kg hockey puck is initially moving at 21.2 m/s [W] along the ice. The coeffi cient of…

A: Given Data:Mass Initial speed Coefficient of kinetic friction To Determine:(a). The speed (v) of the…

Q: block of mass m= 5 Kg is sent sliding up a large plane inclined at 0 = 37° while a horizontal force…

A: Given:Mass of block: m=5 kgMagnitude of external force: F=50 NCoefficient of kinetic friction:…

Q: A 5.0-kg rock is dropped, initially at rest, from a 6.0- m-high second story window. What will be…

A: Given data: Mass (m) = 5.0 kg Initial velocity (v0) = 0 m/s Height (h) = 6.0 m Required: The kinetic…

Q: QUESTION 4 In Unit EM, you saw how contact push/pull interactions can be described using ideas about…

A: (A) This statement is consistent because: As we know, F = ma…

Q: 357 kg car is moving at 35–. The driver then accelerates at 3.5 for 18.3s s2 a. How fast is the car…

A: given m=1857 kg initial velocity u=35 m/s acceleration a= 3.5 m/s2 t=18.3 s v = u…

Q: The 15 lb suitcase is released from rest at C. After it slides down the smooth ramp, it strikes the…

A: Given Mass of suitcase A mA = 15 lb Mass of suitcase B mB = 10 lb…

Q: A freight car in a park moves along a frictionless level railroad track at constant speed. The…

A: Given:A freight car moves along a frictionless level railroad track at constant speed.The freight…

Q: MY NOTES ASK YOUR TEACHER A skier starts from rest at the top of a hill that is inclined at 9.3°…

Q: block of mass m= 5 Kg is sent sliding up a large plane inclined at 0 = 37° while a horizontal force…

A: The block of mass 5 kg is placed at a 37o inclined surface. This block is being pushed up the…

Q: L00-kg block with an initial velocity of 5.00 m/s down the rack

Q: A 150g baseball is thrown with a speed of 40 mls. It is hit straight back towards the piłcher at a…

A: Given data: Mass (m) = 150 g = 0.150 g Initial velocity of ball (v0) = 40 m/s Final velocity of ball…

Q: Suppose a vehicle skids on a pavement and leaves 208 feet of skid marks after coming to a complete…

A: Given: Braking distance=208ft friction factor=0.4

Q: A constant applied force Fp of 15.0 N pushes a box with a mass m = 8.00 kg a distance x = 15.0 m…

A: The final velocity of the box at 15m is 3.49m/sThe new applied force is 3.248NExplanation:Step…

Q: e spring in the figure has a spring constant of 1100 N/m. It is ompressed 17.0 cm, then launches a…

Q: A block of wood is pulled by a horizontal string across a rough surface at a constant velocity with…

Q: 1. ATbar ski lift drags 11 skiers with a combined mass of 655 kg along a rope tow for 900 m using an…

A: NOTE: According to the guidelines, we can only solve one question per post or three sub-parts of a…

Q: A 1.0 kg block it’s on an incline plane set at an angle of 20 degrees with respect to the…

Q: ox with mass of 75.0 kg slides down on an incline plane with an angle of 15° and at bottom of…

Q: Minimum drag occurs at the mimimum value of the following equation D = СD+aС² CL Where D is the…

A: Given,The drag equation, For the minimum value of Drag,

Q: A particle of mass 6kg moves according to the equation x (t) =10t², where x is in meters and t is in…

A: Given: The mass of the particle is 6 kg. The equation of the position is xt=10t2.

Q: A constant applied force F, of 15.0 N pushes a box with a mass m = 7.00 kg a distance x = 15.0 m…

A: Given Information:- Mass of the box is m=7.00 kg. Applied force is Fp=15.0 N. Coefficient of kinetic…

Q: The conveyor belt delivers each 14-kg crate to the ramp at A such that the crate's speed is vA = 2.5…

A: We have to find v

Q: Move over Jeff Bezos, this invention is about to make you the richest person in the world. You have…

A: The mass of the OYOY M=94.0 kg The radius of the cylinder: R=0.810 m The radius of the massless…

Q: Calculate the final speed of the 2.00-kg object that is pushed for d =25.0 m by the F-50.0 N forc…

Q: A constant applied force Fp of 15.0 N pushes. box with a a distance m= 7.00 Kg across X = 15.0 m…

Q: In a pickup game of dorm shuffleboard, students crazed by final exams use a broom to propel a…

A: Given that,mass of book, m=4.6 kgdistance travelled, s=0.61 mforce applied, F=47 Nfinal speed, v=1.4…

Topic Video

Question

Final position
kv
A small block of mass m slides to the left on a frictionless,
horizontal surface with speed v. Then, the block slides up a
m
rough ramp that has an incline angle of 0. The coefficient of
Rough surface
Initial position
kinetic friction between the ramp and box is µ. The
V
acceleration due to gravity is g.
m
Frictionless surface
What is the height h of the block when its speed up the ramp
equals kv, where 0 < k < 1?
h =

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Question 2 Figure 2 shows a 2-story steel frame with h = 4 m and b = 6 m, determine the equivalent horizontal forces (EHF) for both floors under the following actions: Dead load = 20 kN/m Imposed load = 12 kN/m Students can make their own rational assumptions for any information which they think is required but not provided. Clear state the assumptions and the corresponding justifications. W W b Figure 2 h
öaalg äbäi A horizontal force of 1.5 N acts on a 0.2kg mass to accelerate it along a horizontal path. How fast is the mass going after acceleration from rest through 0.3 m? Neglect the *.friction 2.1 m/sec 3.66 m/sec 2.54 m/sec
A block of mass 10kg from rest experiences a constant force of 10N for 5 seconds across a level frictionless surface, after the force is taken off it travels 20 meters until it reaches an area with frictions, still on a level surface. It takes 8 seconds for the block to stop: What is the normal force of the block? What is the force due to kinetic friction? What is the coefficient of kinetic friction?
time = 0 time = t -10 kinetic friction A block slides on a horizontal plane. The initial speed is vo = 2.5 m/s. - V The block slows down because of friction; the coefficient of kinetic friction is 0.100. At time t the speed is vo/2. What is t? (in s) OA: 1.089 OB: 1.274 OC: 1.491 OD: 1.744 OE: 2.041 OF: 2.388 OG: 2.794 OH: 3.269
Question 10 A 10.0 kg child on a 5.0 kg sled, starting from rest, goes down a frictionless hill with a height of 3.25 m. As soon as it reaches the bottom of the hill the sled hits a gravel patch on level ground with a coefficient of friction of 0.72. How far does the sled travel before coming to a stop? (1017) A) 02.34 m B) 067.71 m C) 00.16 m D) 035.10 m E) 04.51 m
QUESTION 28 You push a 80-kg file cabinet to the right on a frictionless horizontal surface with a force of 175 N from rest, the cabinet moves a distance of 12 m. What is the final speed of the cabinet, in m/s? Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.
Please solve and answer the question correctly. Thank you!
Asap plzzz
Move over Jeff Bezos, this invention is about to make you the richest person in the world. You have just invented the OyOy (that's YoYo spelled backwards). It is the very latest in home safety and so easy to use! If your building is on fire, simply reach out and grab the cord on the Oyoy and you will be lowered safely toward the ground at a low velocity. The OyOy has a total mass M = 106.0 kg and is shaped like a cylinder of radius R = 0.835 meters. The secret to the operation of the OyOy is its patented shaft whose radius is only r = 0.0830 meters. The cord is wound around the small shaft and this is the secret to your low velocity. Outer Radius = R Spindle Radius = r Mass = M The FORMULA for the moment of Inertia: I = V(y=0)=? We will use the approximation that the shaft is of negligible mass compared to the total. This means that you can treat the entire OyOy as though it is a solid cylinder with mass M and radius R. Imagine that a customer of mass m = 77.5 kg is using the Oyoy and…
Final position kv A small block of mass m slides to the left on a frictionless, horizontal surface with speed v. Then, the block slides up a m rough ramp that has an incline angle of 0. The coefficient of The Rough surface H. kinetic friction between the ramp and box is Initial position acceleration due to gravity is g. Frictionless surface What is the height h of the block when its speed up the ramp equals kv, where 0 < k < 1? h = help contact us terms of use privacy policy careers about us
A block with a mass (m) of 74.7 kg slides along a horzontal surface. the coefficent of kinetic friction is .31. THe block has an ititial speed (v0) at 11.6m/s in the positive direction. 1) write and expression for the x component of the frictional force of the block experiences Ff in terms of the given variables and variables avaible. 2) what is the magnitude of the frictional force? 3) how for will the block travel before coming to rest.
Help with the following question