Fill the blanks of the following the minimal proof outline, and convert it to a full proof outline. Con-sider a/b to be truncating integer division: that is, a/b is the greatest integer less than or equal to ,e.g., 1/2 = 0.{n > 0}i:= n;{inv{decwhile (i > 1) {i := i / 2}{n > 0 A i = 1}

Approach: 1- There is the first condition like n greater than zero (n>0). It means the n value…

Fill the blanks of the following the minimal proof outline, and convert it to a full proof outl er a/b to be truncating integer division: that is, a/b is the greatest integer less than or ec -, 1/2 = 0. {n > 0} i := n; {inv . {dec while (i >1) { i := i /2 {n > 0 ^ i = 1}

Fill the blanks of the following the minimal proof outline, and convert it to a full proof outl er a/b to be truncating integer division: that is, a/b is the greatest integer less than or ec -, 1/2 = 0. {n > 0} i := n; {inv . {dec while (i >1) { i := i /2 {n > 0 ^ i = 1}

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Fill the blanks of the following the minimal proof outline, and convert it to a full proof outline. Con-
sider a/b to be truncating integer division: that is, a/b is the greatest integer less than or equal to ,
e.g., 1/2 = 0.
{n > 0}
i:= n;
{inv
{dec
while (i > 1) {
i := i / 2
}
{n > 0 A i = 1}

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