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Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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V probe 1 V probe 2 100 nF С1 + V1 R1 1k 2.12V / 200HZ The source is only generating power whereas R and C consumer power. To calculate power in all elements we need to calculate current passing through each element and voltage across each element 1. Measure RMS voltage of R1= 0.264 V 2. RMS mesh current magnitude I=V (vp2)/R1=0.264mA 3. Phase Angle = 82.84° due to capacitive element the current leads to voltage. 4. The current phasor is: 0.264 Z 82.84 mA ||
Transcribed Image Text:V probe 1 V probe 2 100 nF С1 + V1 R1 1k 2.12V / 200HZ The source is only generating power whereas R and C consumer power. To calculate power in all elements we need to calculate current passing through each element and voltage across each element 1. Measure RMS voltage of R1= 0.264 V 2. RMS mesh current magnitude I=V (vp2)/R1=0.264mA 3. Phase Angle = 82.84° due to capacitive element the current leads to voltage. 4. The current phasor is: 0.264 Z 82.84 mA ||
RMS Current (mA) RMS Voltage (V) RI j Power (mW) iIvi iPvi vp, vP2 vP,-vP R, C, *Current on IR=v p;!R, it's a phasor with magnitude and angle. The current thru R i the same current in the voltage source and in the capacitor. *Capacitor voltage Ve=vP;-VP2 *For example: in the first row v p, column |v|40 write the source voltage: 2.12 40°. In the next column RI j, write 2.12/0.
Transcribed Image Text:RMS Current (mA) RMS Voltage (V) RI j Power (mW) iIvi iPvi vp, vP2 vP,-vP R, C, *Current on IR=v p;!R, it's a phasor with magnitude and angle. The current thru R i the same current in the voltage source and in the capacitor. *Capacitor voltage Ve=vP;-VP2 *For example: in the first row v p, column |v|40 write the source voltage: 2.12 40°. In the next column RI j, write 2.12/0.
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