Fill in the table below and answer the questions using these formulas. pH = -log [H*] pOH = -log [OH] Kw= [H*][OH-] Kw = 1.0x 10-14 [H*]= antilog(-pH) [OH]= antilog(-pOH) pH + pOH = 14 [H*] [OH ] pH pOH Acid/Base 2.0 x 10-7 6.9 x 10-3 9.5 5.92 4.8 2.09 x 10-11 5.14 x 10-7 4.13 x 10-7 7.90
Fill in the table below and answer the questions using these formulas. pH = -log [H*] pOH = -log [OH] Kw= [H*][OH-] Kw = 1.0x 10-14 [H*]= antilog(-pH) [OH]= antilog(-pOH) pH + pOH = 14 [H*] [OH ] pH pOH Acid/Base 2.0 x 10-7 6.9 x 10-3 9.5 5.92 4.8 2.09 x 10-11 5.14 x 10-7 4.13 x 10-7 7.90
Introductory Chemistry: A Foundation
8th Edition
ISBN:9781285199030
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter16: Acids And Bases
Section: Chapter Questions
Problem 68AP: Which of the following conditions indicate a basic solution? pOH = 11.21 pH = 9.42 (OH’] > IH+| |OH]...
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Can you please help me thankyou
![Fill in the table below and answer the questions using these formulas.
pH = -log [H*]
pOH = -log [OH-] Kw = [H+][OH-]
Kw = 1.0x 10-14
[H*]= antilog(-pH)
[OH]= antilog(-pOH)
рH + рон - 14
[H+]
[OH ]
pH
POH
Acid/Base
2.0 x 10-7
6.9 x 10-3
9.5
5.92
4.8
2.09 x 10-11
5.14 x 10-7
4.13 x 10-7
7.90](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d4e4b40-b2ea-45f4-bfdb-1cfedbad28c0%2F698697b3-0b12-4a76-bb29-8d0408ce53ed%2Fx3gfqo2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Fill in the table below and answer the questions using these formulas.
pH = -log [H*]
pOH = -log [OH-] Kw = [H+][OH-]
Kw = 1.0x 10-14
[H*]= antilog(-pH)
[OH]= antilog(-pOH)
рH + рон - 14
[H+]
[OH ]
pH
POH
Acid/Base
2.0 x 10-7
6.9 x 10-3
9.5
5.92
4.8
2.09 x 10-11
5.14 x 10-7
4.13 x 10-7
7.90
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