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Fill in the proof below. To prove the resolution law: p v Q, ~p v R : . (therefore) Q v R You can use the rule of inference; do not use the resolution law in your proof state the reason for each step, including line reference. The conditional identity is useful: p → Q = `pvQ 1, p v R 2, p →R 3, pvQ 4, 5, 6, 7, 8, 9, QVR Hypothesis Conditional identity, 1 Hypothesis Hypothetical syllogism, (line(s) #

Fill in the proof below. To prove the resolution law: p v Q, ~p v R : . (therefore) Q v R You can use the rule of inference; do not use the resolution law in your proof state the reason for each step, including line reference. The conditional identity is useful: p → Q = `pvQ 1, p v R 2, p →R 3, pvQ 4, 5, 6, 7, 8, 9, QVR Hypothesis Conditional identity, 1 Hypothesis Hypothetical syllogism, (line(s) #

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Fill in the proof below. To prove the resolution law: p v Q, ~p v R : . (therefore) Q v R You can use the rule of inference; do not use the resolution law in your proof state the reason for each step, including line reference. The conditional identity is useful: p → Q = `p v Q 1, ~pvR Hypothesis 2, p →R Conditional identity, 1 3, p v Q Hypothesis 4, 5, 6, 7, 8, 9, QVR Hypothetical syllogism, (line(s) #
Transcribed Image Text:Fill in the proof below. To prove the resolution law: p v Q, ~p v R : . (therefore) Q v R You can use the rule of inference; do not use the resolution law in your proof state the reason for each step, including line reference. The conditional identity is useful: p → Q = `p v Q 1, ~pvR Hypothesis 2, p →R Conditional identity, 1 3, p v Q Hypothesis 4, 5, 6, 7, 8, 9, QVR Hypothetical syllogism, (line(s) #
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