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А D Given: AABC, AB = CB, BD – median to AC , ЕЕ АВ, FE BC, AE = CF Prove: AADE = ACDF, ABDE = ABDF AADE = A by rule

А D Given: AABC, AB = CB, BD – median to AC , ЕЕ АВ, FE BC, AE = CF Prove: AADE = ACDF, ABDE = ABDF AADE = A by rule

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Write the complete proof in your paper homework, and for online (only) complete the probing statement (if any) that is a part of your proof or related to it. В А C D Given: AABC, АВ 3 СВ, BD - - median to AC, ЕЕ АВ, FE BC, AE = CF Prove: AADE = ACDF, ABDE = ABDF AADE = A by rule ▼
Transcribed Image Text:Write the complete proof in your paper homework, and for online (only) complete the probing statement (if any) that is a part of your proof or related to it. В А C D Given: AABC, АВ 3 СВ, BD - - median to AC, ЕЕ АВ, FE BC, AE = CF Prove: AADE = ACDF, ABDE = ABDF AADE = A by rule ▼
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