Fill in the blanks:(7.13) Using a current of 4.75 A, how manyminutes does it take to plate a sculpturewith 1.50 g of Cu from a CuS04 solution?(Cu 63.546 g/mol)Analysis/Strategy: mass of Cu ® mol Cu® mol e" (or Faraday) ® coulombs ®time in minutes (given currentinamperes)Reduction half-reaction of coppersolution to copper metal: Cu*2(aq) ·+e¯ ® Cu(s)copper solution, CUSO4, has the ions:[Cu*2_SOq]Answer: The time needed to plate out asculpture isminutes. (3sig fig)

Answered: Image /qna-images/answer/6c15b6a6-7f4c-4b7b-916a-39aef3320b15.jpg

Fill in the blanks: (7.13) Using a current of 4.75 A, how many minutes does it take to plate a sculpture with 1.50 g of Cu from a CuS04 solution? (Cu 63.546 g/mol) Analysis/Strategy: mass of Cu ® mol Cu ® mol e" (or Faraday) ® coulombs ® R time in minutes (given current in amperes) Reduction half-reaction of copper solution to copper metal: Cu*2(aq) · Cu+2, + e¯ ® Cu(s) copper solution, CUSO4, has the ions: [Cu*2 _SO42] Answer: The time needed to plate out a sculpture is minutes. (3 sig fig)

Fill in the blanks: (7.13) Using a current of 4.75 A, how many minutes does it take to plate a sculpture with 1.50 g of Cu from a CuS04 solution? (Cu 63.546 g/mol) Analysis/Strategy: mass of Cu ® mol Cu ® mol e" (or Faraday) ® coulombs ® R time in minutes (given current in amperes) Reduction half-reaction of copper solution to copper metal: Cu2(aq) · Cu+2, + e¯ ® Cu(s) copper solution, CUSO4, has the ions: [Cu2 _SO42] Answer: The time needed to plate out a sculpture is minutes. (3 sig fig)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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