Fill in the blanks: (7.13) Using a current of 4.75 A, how many minutes does it take to plate a sculpture with 1.50 g of Cu from a CuS04 solution? (Cu 63.546 g/mol) Analysis/Strategy: mass of Cu ® mol Cu ® mol e" (or Faraday) ® coulombs ® R time in minutes (given current in amperes) Reduction half-reaction of copper solution to copper metal: Cu*2(aq) · Cu+2, + e¯ ® Cu(s) copper solution, CUSO4, has the ions: [Cu*2 _SO42] Answer: The time needed to plate out a sculpture is minutes. (3 sig fig)

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Fill in the blanks:
(7.13) Using a current of 4.75 A, how many
minutes does it take to plate a sculpture
with 1.50 g of Cu from a CuS04 solution?
(Cu 63.546 g/mol)
Analysis/Strategy: mass of Cu ® mol Cu
® mol e" (or Faraday) ® coulombs ®
time in minutes (given current
in
amperes)
Reduction half-reaction of copper
solution to copper metal: Cu*2(aq) ·
+
e¯ ® Cu(s)
copper solution, CUSO4, has the ions:
[Cu*2_SOq]
Answer: The time needed to plate out a
sculpture is
minutes. (3
sig fig)
Transcribed Image Text:Fill in the blanks: (7.13) Using a current of 4.75 A, how many minutes does it take to plate a sculpture with 1.50 g of Cu from a CuS04 solution? (Cu 63.546 g/mol) Analysis/Strategy: mass of Cu ® mol Cu ® mol e" (or Faraday) ® coulombs ® time in minutes (given current in amperes) Reduction half-reaction of copper solution to copper metal: Cu*2(aq) · + e¯ ® Cu(s) copper solution, CUSO4, has the ions: [Cu*2_SOq] Answer: The time needed to plate out a sculpture is minutes. (3 sig fig)
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