Fill in the blank by using drag and drop one of the following answers (some options will not be used): Part 1: Given that Z is a standard normal random variable, compute the following probabilities: a) P(Z < 2.2) = b) P(Z >-0.6) = c) P(Z <-2.36) = d) P(Z s ) = 0.6179 Part 2: The Italian National Bank is reviewing its current account service charges and interest payment procedures. The average daily balance is Normally distributed, with a mean of £490 and a standard deviation of £110, according to the bank. The probability of current users having more than £732 in their accounts is The probability of current users having between £424 and £523 in their accounts is 0.9495 -2.44 0.8849 0.9861 0.7257 0.0091 0.9357 0.3 0.0505 0.8776 0.3436 0.9448 0.0139

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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Fill in the blank by using drag and drop one of the following answers (some options will not be used):
Part 1: Given that Z is a standard normal random variable, compute the following probabilities:
a) P(Z ≤ 2.2) =
b) P(Z >-0.6) =
c) P(Z < -2.36)
=
d) P(Z <
) = 0.6179
Part 2: The Italian National Bank is reviewing its current account service charges and interest payment
procedures. The average daily balance is Normally distributed, with a mean of £490 and a standard
deviation of £110, according to the bank.
The probability of current users having more than £732 in their accounts is
The probability of current users having between £424 and £523 in their accounts is
0.9495 -2.44 0.8849 0.9861 0.7257 0.0091 0.9357 0.3
0.0505 0.8776 0.3436 0.9448 0.0139
Transcribed Image Text:Fill in the blank by using drag and drop one of the following answers (some options will not be used): Part 1: Given that Z is a standard normal random variable, compute the following probabilities: a) P(Z ≤ 2.2) = b) P(Z >-0.6) = c) P(Z < -2.36) = d) P(Z < ) = 0.6179 Part 2: The Italian National Bank is reviewing its current account service charges and interest payment procedures. The average daily balance is Normally distributed, with a mean of £490 and a standard deviation of £110, according to the bank. The probability of current users having more than £732 in their accounts is The probability of current users having between £424 and £523 in their accounts is 0.9495 -2.44 0.8849 0.9861 0.7257 0.0091 0.9357 0.3 0.0505 0.8776 0.3436 0.9448 0.0139
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