File Edit Format View Help LONGEST COMMONE SUB SEQUENCE Given two sequences X and Y, we want to find Z i.e., the longest common subsequence (LCS) of both X and Y. Because we know that subsequences of interest are of length >= a and <= b, we threshold the LCS definition to |Z| in [a, b] (where |Z| is the sequence length). public class Solution S 2 static int longSub (String a, String b) { int m= a.length(); int n = b.length(); int 1CS[][] = new int[m + 1][n+ 1]; for (int i = 0; i <= m; i++) { for (int j = 0; j <= n; j++) { if (i == 0 || j == 0) { lcs[i][j] = 0; else if (a.charAt(i - 1) == b.charAt(j - 1)) { 1cs[i][j] = 1cs[i-1][j - 1] + 1; } else{ 1cs[i][j] = Math.max (1CS [i-1][j], lcs[i][j - 1]); } } return 1CS[m][n];

File Edit Format View Help LONGEST COMMONE SUB SEQUENCE Given two sequences X and Y, we want to find Z i.e., the longest common subsequence (LCS) of both X and Y. Because we know that subsequences of interest are of length >= a and <= b, we threshold the LCS definition to |Z| in [a, b] (where |Z| is the sequence length). public class Solution S 2 static int longSub (String a, String b) { int m= a.length(); int n = b.length(); int 1CS[][] = new int[m + 1][n+ 1]; for (int i = 0; i <= m; i++) { for (int j = 0; j <= n; j++) { if (i == 0 || j == 0) { lcs[i][j] = 0; else if (a.charAt(i - 1) == b.charAt(j - 1)) { 1cs[i][j] = 1cs[i-1][j - 1] + 1; } else{ 1cs[i][j] = Math.max (1CS [i-1][j], lcs[i][j - 1]); } } return 1CS[m][n];

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter3: Data Representation

Section: Chapter Questions

Problem 1PE

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