Figure shows a parallel-plate capacitor with a plate area A = 7.89 cm² and plate separation d = 4.62 mm. The top half of the gap is filled with material of dielectric constant K1 = 11.0; the bottom half is filled with material of dielectric constant k2 = 12.0.
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Q: The figure shows a parallel-plate capacitor of plate area A = 11.5 cm2 and plate separation 2d= 7.40…
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A: Solution:Let:C1 = ε0A2k12d = ε0A k12dC2 = ε0A2k22d = ε0A k22dC3 = ε0A2k32d = ε0A k32d
Q: Figure shows a parallel-plate capacitor with a plate area A = 7.89 cm² and plate separation d = 4.62…
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- 3. The Figure below shows a parallel-plate capacitor of plate area A= 10.5 cm² and plate separation 2d=7.12 mm. The left half of the gap is filled with material of dielectric constant K₁= 21.0; the top of the right half is filled with material of dielectric constant K₂ = 42.0; the bottom of the right half is filled with material of dielectric constant K3 = 58.0. What is the capacitance? 2d K₁An air-filled parallel-plate capacitor has a capacitance of 2 pF. The plate separation is then halved and a wax dielectric is inserted, completely filling the space between the plates. As a result, the capacitance becomes 8 pF. The dielectric constant of the wax is:A parallel-plate air capacitor of area A = 10.5 cm2 and plate separation of d = 3.60 mm is charged by a battery to a voltage of 51.0 V. What is the charge on the capacitor?
- An initially uncharged air-filled capacitor is connected to a 3.29 V charging source. As a result, the capacitor acquires 9.89 x 10- C of charge. Then, while the capacitor remains connected to the charging source, a sheet of dielectric material is inserted between its plates, completely filling the space. The dielectric constant k of this substance is 7.61. Find the voltage V across the capacitor and the charge Qf stored by it after the dielectric is inserted and the circuit has returned to a steady state. V = V Qt = CA parallel plate, air filled capacitor, has plates of area 0.61 m2 and a separation of 0.1 mm.What is its capacitance? (Units: nF=10-9F)A capacitor is made with plates of area A = 0.255 m2, separated by a distance d = 0.386 mm. Between the plates is a layer of a material with dielectric constant κ = 2.15. What is the capacitance of the capacitor? Your answer should be in nano-farads (nF)