Figure shows a graph of potential energy U versus positionz of a 2.0 kg particle that can travel only along an z axis under action of a conservative force. In unit-vector notation, what is the force F, on the particle when it is located at I=2 m? U(I) 6. 2. x(m) ol 12 3 4 6 7 8 Select one: O F (-4N)j O F-(-2N)i O F-(4N)i
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- A particle moves along the x-axis with the potential energy shown. Find the X-component of the force on the particle when it is at x=4 m.A luggage handler pulls a 20.0 kg suitcase up a ramp inclined at 34.0 ∘∘ above the horizontal by a force F⃗ → of magnitude 163 NN that acts parallel to the ramp. The coefficient of kinetic friction between the ramp and the incline is μk = 0.300. The suitcase travels 3.70 mm along the ramp. Calculate the work done on the suitcase by F⃗ →. Calculate the work done on the suitcase by the gravitational force. Calculate the work done on the suitcase by the normal force. Calculate the work done on the suitcase by the friction force. Calculate the total work done on the suitcase. If the speed of the suitcase is zero at the bottom of the ramp, what is its speed after it has traveled 3.70 mm along the ramp?A 7.00-kg particle moves from the origin to position ©, having coordinates x = 6.50 m and y = 6.50 m as shown in the figure. One force on the particle is the gravitational force acting in the negative y direction. Using the equation (W = FAr cos 0 = F · Ař), calculate the work done by the gravitational force in going from O to © along the following paths. у (m) B (х, у) x (m) (a) the purple path (o0©) (b) the red path (O®© (c) the blue path (O© (d) Your results should all be identical. Why? This answer has not been graded yet.
- Protons and neutrons (together called nucleons) are held together in the nucleus of an atom by a force called the strong force. At very small separations, the strong force between two nucleons is larger than the repulsive electrical force between two protons--hence its name. But the strong force quickly weakens as the distance between the protons increases. A well-established model for the potential energy of two nucleons interacting via the strong force is U=U0[1−e−x/x0] where x is the distance between the centers of the two nucleons, x0 is a constant having the value x0 = 2.0 × 10−15 m, and U0 = 6.0 × 10−11 J. Quantum effects are essential for a proper understanding of nucleons, but let us innocently consider two neutrons as if they were small, hard, electrically neutral spheres of mass 1.67 ×10−27 kg and diameter 1.0 × 10−15 m. Suppose you hold two neutrons 9.0 × 10−15 m apart, measured between their centers, then release them.What is the speed of each neutron as they crash…Problem Thirteen. A potential energy function is given by U(r)=U2 where o = 2.00 m r r and U, = 1.00 J. Find the magnitude of the force at r= 1.00 m. Give an answer in kN. 25.) (A) 280 (В) 106 (С) 420 (D) 470 (E) 530Can someone help with second question? Thanks
- Problem 4: A 2.00 kg object moving in the x-y plane is under the influence of a force describe by the potential energy U (x,y) = (4.00 J/m³)x3 – (2.00 J/m4)y“. What is the magnitude and direction (angle) of the acceleration of the object at a point x=1 m and y = 2 m?The figure below shows a plot of potential energy U versus position x of a 0.96 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) In the graphs, the potential energies are UA = 10.0 J, Ug = 25.0 J, and UC = 35.0 J. (r) Ucr UB 2 4 6 x (m) The particle is released at x = 4.5 m with an initial speed of 8.5 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.0 m, what is its speed there, and if it cannot, what is its turning point? ---Select-- C ---Select- (b) What are the magnitude and direction of the force on the particle as it begins to move to the left of x = 4.0 m? magnitude N direction Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.5 m at speed 8.5 m/s. (c) If the particle can reach x = 7.0 m, what is its speed there, and if it cannot, what is its turning point? Select CPlease asap
- A 1700 kg car starts up a 130 m long hill at a speed of 20.0 m/s. If the propulsive force (up the slope) is 15.0 kN, while the resistive force (due to friction/AR) is 8.79 kN, then determine the car's kinetic energy when it reaches a vertical height of 48.1 m at the top of the hill. can you please write it down instead so I can follow it betterThe figure here shows a plot of potential energy U versus position x of a 0.878 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA-15.0J, Us - 35.0 J and Uc-45.0 J. The particle is released at x -4.50 m with an initial speed of 7.99 m/s, headed in the negative x direction. (a) If the particle can reach x -1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x- 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x - 4.50 m at speed 7.99 m/s. (d) If the particle can reach x - 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x-5.00 m? (0)2 Ucr UB UA 2 (a) Number (b) Number 10 4 x (m) (c) positive (+x) (e)…O 0 Consider again pulling a 60 m rope up a cliff face, where the rope has a mass of 66 g/m. At what point is exactly half the work performed? Total work performed is 1,164.24 J 18.57 and 101.43 O 16.52 and 102.33 O 17.40 and 100.02 17.57 and 102.43 Submit Page 2 of 2 Clear form Back