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Figure P8.13 provides steady-state operating data for a solar power plant that operates on a Rankine cycle with Refrigerant 134a as its working fluid. The turbine and pump operate adiabatically. The rate of energy input to the collectors from solar radiation is by the refrigerant as it passes through the collectors. Determine the solar collector surface area, in m' per kW of power developed by the plant.

Figure P8.13 provides steady-state operating data for a solar power plant that operates on a Rankine cycle with Refrigerant 134a as its working fluid. The turbine and pump operate adiabatically. The rate of energy input to the collectors from solar radiation is by the refrigerant as it passes through the collectors. Determine the solar collector surface area, in m' per kW of power developed by the plant.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Figure P8.13 provides steady-state operating data for a solar power plant that operates on a Rankine cycle with Refrigerant 134a as its working fluid. The turbine and pump operate adiabatically. The rate of energy input to the collectors from solar radiation is 0.3 kW per m² of collector surface area, with 60% of the solar input to, the collectors absorbed by the refrigerant as it passes through the collectors. Determine the solar collector surface area, in m per kW of power developed by the plant. = 0.3 kW/m? Turbine Solar Collectors Condenser Pump P (bar) h (kJ/kg) State 1 18 276.83 1 2. 0.9952 261.01 86.78 7 4 18 87.93
Transcribed Image Text:Figure P8.13 provides steady-state operating data for a solar power plant that operates on a Rankine cycle with Refrigerant 134a as its working fluid. The turbine and pump operate adiabatically. The rate of energy input to the collectors from solar radiation is 0.3 kW per m² of collector surface area, with 60% of the solar input to, the collectors absorbed by the refrigerant as it passes through the collectors. Determine the solar collector surface area, in m per kW of power developed by the plant. = 0.3 kW/m? Turbine Solar Collectors Condenser Pump P (bar) h (kJ/kg) State 1 18 276.83 1 2. 0.9952 261.01 86.78 7 4 18 87.93
Equation Sheets 1st Law T(K)=TCC)+273.15 COP AU +AKE +APE -Q-W dKE dPE dU 1- Properties A-u+ P Compressiblity -Q- di Closed Systems RT P P, - 2nd Law A-AC,7, -7) P. Saturated region Constant Pressure Work W- PV,-) dt v=v, +v, -v,) =", +xtu, -,) Polytropic Work Polytropic process PV" - constant 1- Open Systems Mass Subcooled region T.P)= (T)=v,() Cycles Desired Output Required Input dm T.P) = (T)=u,T) di T.P) =u, (T)-P*v, (r) VA Heat engine (Power plant) Ideal Gas P-RT 1st Law PV = mRT dE R-0.2870klkg K e-1- dt 2nd Law Air Conditioner and Refrigerator COP. W. L-1 Ideal Gas isentropic dt PP. 2. Isentropic efficiencies COP (h -h) Isentropie Turbine Work (h -h) Actual Turbine Work Isentropic Compressor Work (h, -k) Actual Compressor Work Heat Pump (h, -4) P = P Iseniropic Pump Work (P, - P) Actual Pump Work (h, -h,) Regeneration optimal flow split
Transcribed Image Text:Equation Sheets 1st Law T(K)=TCC)+273.15 COP AU +AKE +APE -Q-W dKE dPE dU 1- Properties A-u+ P Compressiblity -Q- di Closed Systems RT P P, - 2nd Law A-AC,7, -7) P. Saturated region Constant Pressure Work W- PV,-) dt v=v, +v, -v,) =", +xtu, -,) Polytropic Work Polytropic process PV" - constant 1- Open Systems Mass Subcooled region T.P)= (T)=v,() Cycles Desired Output Required Input dm T.P) = (T)=u,T) di T.P) =u, (T)-P*v, (r) VA Heat engine (Power plant) Ideal Gas P-RT 1st Law PV = mRT dE R-0.2870klkg K e-1- dt 2nd Law Air Conditioner and Refrigerator COP. W. L-1 Ideal Gas isentropic dt PP. 2. Isentropic efficiencies COP (h -h) Isentropie Turbine Work (h -h) Actual Turbine Work Isentropic Compressor Work (h, -k) Actual Compressor Work Heat Pump (h, -4) P = P Iseniropic Pump Work (P, - P) Actual Pump Work (h, -h,) Regeneration optimal flow split
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