Figure below shows a 0.41- kg block sliding from A to B along a frictionless surface. When the block reaches B, it continues to slide along the horizontal surface BC where a kinetic frictional force acts. As a result, the block slows down, coming to rest at C. The kinetic energy of the block at A is 37 J, and the heights of A and B are 12.0 and 7.0 m above the ground, respectively. What is the kinetic energy of the block when it reaches B? A hA = 12.0 m B C hB = 7.0 m hc= 7.0 m

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Chapter1: Units, Trigonometry. And Vectors
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Figure below shows a 0.41- kg block sliding from A to B along a frictionless surface. When
the block reaches B, it continues to slide along the horizontal surface BC where a kinetic
frictional force acts. As a result, the block slows down, coming to rest at C. The kinetic
energy of the block at A is 37 J, and the heights of A and B are 12.0 and 7.0 m above the
ground, respectively.
What is the kinetic energy of the block when it
reaches B?
A
hA = 12.0 m
B
C
hB = 7.0 m hc = 7.0 m
Transcribed Image Text:Figure below shows a 0.41- kg block sliding from A to B along a frictionless surface. When the block reaches B, it continues to slide along the horizontal surface BC where a kinetic frictional force acts. As a result, the block slows down, coming to rest at C. The kinetic energy of the block at A is 37 J, and the heights of A and B are 12.0 and 7.0 m above the ground, respectively. What is the kinetic energy of the block when it reaches B? A hA = 12.0 m B C hB = 7.0 m hc = 7.0 m
How much work does the kinetic frictional force do during the BC segment of the trip?
Transcribed Image Text:How much work does the kinetic frictional force do during the BC segment of the trip?
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