Figure (a) shows three plastic sheets that are large, parallel, and uniformly charged. Figure (b) gives the component of the net electricfield along an x axis through the sheets. The scale of the vertical axis is set by Es = 4.8 × 105 N/C. What is the ratio of the charge densityon sheet 3 to that on sheet 2?Number(a)E (105 N/C)Units3x(b)x

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Answered: Figure (a) shows three plastic sheets…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter25: Gauss’s Law

Section: Chapter Questions

Problem 43PQ: The nonuniform charge density of a solid insulating sphere of radius R is given by = cr2 (r R),...

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A cylinder of length L=5m has a radius R=2 cm and linear charge density 2=300 µC/m. Although the linear charge density is a constant through the cylinder, the charge density within the cylinder changes with r. Within the cylinder, the charge density of the cylinder varies with radius as a function p( r) =p.r/R. Here R is the radius of the cylinder and R=2 cm and p, is just a constant that you need to determine. b. Find the constant po in terms of R and 2. Then plug in values of R and 1. to find the value for the constant p. c. Assuming that L>>R, use Gauss's law to find out the electric field E inside the cylinder (rR) in terms of 1. and R. d. Based on your result from problem c, find the electric field E at r=1cm and r=4cm.
The volume charge density ρ for a spherical charge distribution of radius R = 6.00 mm is not uniform. The figure shows ρ as a function of the distance r from the center of the distribution. a) Calculate the electric field at r = 5.00 mm .Express your answer with the appropriate units. b) Calculate the electric field at r = 7.00 mm .Express your answer with the appropriate units
Positive charge is distributed in a sphere of radius R that is centered at the origin. Inside the sphere, the electric field is Ē(r) = kr-1/4 f, where k is a positive constant. There is no charge outside the sphere. a) How is the charge distributed inside the sphere? In particular, find an equation for the charge density, p. b) Determine the electric field, E(r), for r > R (outside the sphere). c) What is the potential difference between the center of the sphere (r = 0) and the surface of the sphere (r = R)? d) What is the energy stored in this electric charge configuration?
The volume charge density ρ for a spherical charge distribution of radius R= 6.00 mm is not uniform. (Figure 1) shows ρ as a function of the distance r from the center of the distribution. a)Calculate the electric field at r = 1.00 mm. b)Calculate the electric field at r = 1.00 mm.
You are working as an intern for a meteorological laboratory. You are out in the field taking measurements with a device that measures electric fields. You measure the electric field in the air immediately above the Earth's surface to be 139 N/C directed downward. (Assume the radius of the Earth is 6.37 x 106 m.) (a) Determine the surface charge density (in C/m²) on the ground. C/m? (b) Imagine the surface charge density is uniform over the planet. Determine the charge (in C) of the whole surface of the Earth. (e) Determine the Earth's electric potential (in V) due to the charge found in (b). V (d) Determine the difference in potential (in V) between the head and the feet of a person 1.50 m tall. (Ignore any charges in the atmosphere.) V
A circular metal plate of radius 17.2 cm carries a total charge of 1.01 μC and the charge is distributed uniformly over the surface of the plate. Determine the surface charge density on the plate and report your answer in µC/m².
A closed surface with dimensions a = b = 0.208 m and c = 0.3328 m is located as in the figure. The electric field throughout the region is nonuniform and defined by E (a + Bx²) î where x is in meters, a = 5 N/C, and 3 = 6 N/(C · m²). Y E Answer in units of C a x k What is the magnitude of the net charge enclosed by the surface? Answer in units of C. part 2 of 2 What is the sign of the charge enclosed in the surface?
Positive electric charge is uniformly distributed along the y-axis with a linear charge density l. Consider the case where charge is distributed only between points y = +a and y = -a. For points between the +x-axis, graph the x-component of the electric field as a function of x, Ex (x), for values x = a/2 and x = 4a. Consider instead the case where charge is distributed along the entire y-axis with the same charge density l. Using the same graph as in part (a), plot the x-component of the electric field, Ex (x), as function of x for values of x between x = a/2 and x = 4a.
Your answer is partially correct. Figure (a) shows three plastic sheets that are large, parallel, and uniformly charged. Figure (b) gives the component of the net electric field along an x axis through the sheets. The scale of the vertical axis is set by E, 6.6 x 105 N/C. What is the ratio of the charge density on sheet 3 to that on sheet 2? Number -1.65 (a) E (10²³ N/G) Units No units
An infinite cylinder of radius R has a linear charge density X. The volume charge density (C/m³) within the cylinder (r< R) is p(r)=rpo/R. where po = 3X/2TR² Part A Use Gauss's law to find an expression for the electric field E inside the cylinder, r < R, in terms of A and R. Express your answer in terms of the variables r, R, A, and 0. E= Submit ΓΙ ΑΣΦ Request Answer Review ?
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A thin, square, conducting plate 54.0 cm on a side lies in the xy plane. A total charge of 3.20 x 10-8 C is placed on the plate. You may assume the charge density is uniform. (a) Find the charge density on each face of the plate. C/m² (b) Find the electric field just above the plate. magnitude N/C direction upward ◊ (c) Find the electric field just below the plate. magnitude N/C direction downward ↑

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