Figure 3.4 Q3.5. The left common coronary artery has an axisymmetric constriction because of a plaque buildup (Figure 3.5). Given the upstream conditions of a velocity of 20 cm/s (systole) and 12 cm/s (diastole), calculate the velocity at the stenosis throat and the pressure difference between the stenosis throat and the inlet during systole and diastole. Assume that the Bernoulli principle can be used and that the density of blood is 1050 kg/m . Assume that there is no difference in height under these conditions. d= 6 mm d= 15 mm Figure 3.5

Elements Of Electromagnetics
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Figure 3.4
Q3.5. The left common coronary artery has an axisymmetric constriction because of a plaque buildup
(Figure 3.5). Given the upstream conditions of a velocity of 20 cm/s (systole) and 12 cm/s (diastole),
calculate the velocity at the stenosis throat and the pressure difference between the stenosis throat
and the inlet during systole and diastole. Assume that the Bernoulli principle can be used and that the
density of blood is 1050 kg/m . Assume that there is no difference in height under these conditions.
d = 6 mm
d= 15 mm
Figure 3.5
Transcribed Image Text:Figure 3.4 Q3.5. The left common coronary artery has an axisymmetric constriction because of a plaque buildup (Figure 3.5). Given the upstream conditions of a velocity of 20 cm/s (systole) and 12 cm/s (diastole), calculate the velocity at the stenosis throat and the pressure difference between the stenosis throat and the inlet during systole and diastole. Assume that the Bernoulli principle can be used and that the density of blood is 1050 kg/m . Assume that there is no difference in height under these conditions. d = 6 mm d= 15 mm Figure 3.5
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