Figure 1.5.8 shows a slope field and typical solution curves for the equation . (a) Show that every solution curve approaches the straight line y= -x - 1 as x goes to negative infinity. (b) For each of the five values y sub1 = -10, -5, 0, 5, and 10, determine the initial value (accurate to five decimal places) such that y(5) = y sub1for the solution satisfying the initial condition y(-5) = y sub0. Image: Slope field and solution curves for y' = x + y
Figure 1.5.8 shows a slope field and typical solution curves for the equation . (a) Show that every solution curve approaches the straight line y= -x - 1 as x goes to negative infinity. (b) For each of the five values y sub1 = -10, -5, 0, 5, and 10, determine the initial value (accurate to five decimal places) such that y(5) = y sub1for the solution satisfying the initial condition y(-5) = y sub0. Image: Slope field and solution curves for y' = x + y
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Figure 1.5.8 shows a slope field and typical solution curves for the equation . (a) Show that every solution curve approaches the straight line y= -x - 1 as x goes to negative infinity. (b) For each of the five values y sub1 = -10, -5, 0, 5, and 10, determine the initial value (accurate to five decimal places) such that y(5) = y sub1for the solution satisfying the initial condition y(-5) = y sub0.
Image: Slope field and solution curves for y' = x + y
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9
4
-2
-6
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-10
-5
0
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Transcribed Image Text:y
10
8
9
4
-2
-6
-8
-10
-5
0
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