Figure 1: y P = 400 kN 30° 1000 mm A Area 30 mm 20 mm In Figure 1, the equilibrium shear force component at the point A is (in kN) 400sin30 400cos30 400sin30- O 400tan30
Figure 1: y P = 400 kN 30° 1000 mm A Area 30 mm 20 mm In Figure 1, the equilibrium shear force component at the point A is (in kN) 400sin30 400cos30 400sin30- O 400tan30
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter7: Analysis Of Stress And Strain
Section: Chapter Questions
Problem 7.7.23P: Solve the preceding problem if the cross- sectional dimensions are b = 1.5 in. and h = 5.0 in., the...
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![Figure 1:
y
P = 400 kN
30°
1000 mm
A
Area 30 mm
20 mm
In Figure 1, the equilibrium shear force
component at the point A is (in kN)
400sin30
400cos30
400sin30- O
400tan30](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3245cf94-9470-4e52-8d9a-d418a49cd28a%2F29fcea45-7454-43df-b73e-a581a739febf%2F5f04v0o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Figure 1:
y
P = 400 kN
30°
1000 mm
A
Area 30 mm
20 mm
In Figure 1, the equilibrium shear force
component at the point A is (in kN)
400sin30
400cos30
400sin30- O
400tan30
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