Figure 1 shows a truss system for supporting an imposed load (IL) at the end of the triangular cantileverarm. The dead load of the triangular cantilever (DLc) is applied at the centroid (of the triangle) asshown in the figure. The total dead load of the tower of the truss system (excluding the cantilever arm)is transferred through the left (DL₁) and right (DLR) legs to the foundations. The panel length L is equalto 3m. The values of the unfactored dead and imposed loads are:IL = 60KNDLC = 15kNDLL = DLR= 30kNDetermine the maximum design vertical reactions on the left and right foundation for ULS usingEurocode. [Neglect the equivalent horizontal forces (EHF) in your design.]DLLLDLCDLRLFigure 1 [not to scale]IL

Given: Dead loads: DLc=15 kN (acting at the centroid of the triangular cantilever section)…

Figure 1 shows a truss system for supporting an imposed load (IL) at the end of the triangular cantilever arm. The dead load of the triangular cantilever (DLC) is applied at the centroid (of the triangle) as shown in the figure. The total dead load of the tower of the truss system (excluding the cantilever arm) is transferred through the left (DLL) and right (DLR) legs to the foundations. The panel length L is equal to 3m. The values of the unfactored dead and imposed loads are: IL = 60KN DLC = 15kN ● DLL = DLR = 30kN Determine the maximum design vertical reactions on the left and right foundation for ULS using Eurocode. [Neglect the equivalent horizontal forces (EHF) in your design.] ● DLL L DLC DLR L Figure 1 [not to scale] IL

Figure 1 shows a truss system for supporting an imposed load (IL) at the end of the triangular cantilever arm. The dead load of the triangular cantilever (DLC) is applied at the centroid (of the triangle) as shown in the figure. The total dead load of the tower of the truss system (excluding the cantilever arm) is transferred through the left (DLL) and right (DLR) legs to the foundations. The panel length L is equal to 3m. The values of the unfactored dead and imposed loads are: IL = 60KN DLC = 15kN ● DLL = DLR = 30kN Determine the maximum design vertical reactions on the left and right foundation for ULS using Eurocode. [Neglect the equivalent horizontal forces (EHF) in your design.] ● DLL L DLC DLR L Figure 1 [not to scale] IL

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: The members of the truss shown has cross sections of 500 mm2 in tension and 800 mm2 in compression.…

Q: a) The truss in Figure 2-1 consists of four wooden members, ABC, DEF, BE, and CF, which supports…

A: To find the average normal stress in m

Q: Method of Joints 1. The portion of truss shown represents the upper part of a power transmission…

A: There is a rigid structure created by a truss that is a collection of members connected by nodes.…

Q: Determine the force in mimber BD of the truss shown. State wether each member is in tension or…

Q: 200 lb/ft 50 lb/ft" 6 ft- -50 lb/ft E 6 ft B 8 ft C 8 ft 8 ft

Q: The pinned truss in Fig Q1 is subject to a horizontal load of 150kN at Pin C. The strut members AB,…

A: The given diagram is shown below, To determineThe axial stress in each memberThe stabilityof the…

Q: Example 3-7 Determine the force in members BC and MC of the K-truss shown in the figure below. L K J…

A: Finding out member force in BC and MC.

Q: 4m 60⁰ 2kN C 60⁰ 2kN B 8m 30⁰ 2kN A

A: Cut the x-x plane as shown in below solution. Applying equilibrium equation in both x and y…

Q: Q.3) A simply supported wide-flange (see figure below) beam of span length L carries a vertical…

A: Given : Section : W 10 X 30 L = 8.5 ft P = 5 kips Alpha = 26.57 degrees We are asked to determine…

Q: Determine the force in member GF and state if the member is in tension or compression. Express your…

Question

Figure 1 shows a truss system for supporting an imposed load (IL) at the end of the triangular cantilever
arm. The dead load of the triangular cantilever (DLc) is applied at the centroid (of the triangle) as
shown in the figure. The total dead load of the tower of the truss system (excluding the cantilever arm)
is transferred through the left (DL₁) and right (DLR) legs to the foundations. The panel length L is equal
to 3m. The values of the unfactored dead and imposed loads are:
IL = 60KN
DLC = 15kN
DLL = DLR= 30kN
Determine the maximum design vertical reactions on the left and right foundation for ULS using
Eurocode. [Neglect the equivalent horizontal forces (EHF) in your design.]
DLL
L
DLC
DLR
L
Figure 1 [not to scale]
IL

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step by step

Solved in 4 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

1. For the beams shown below: (a) calculate the support reactions. (b) calculate the internal forces at sections A and B and indicate if the internal forces are positive or negative. F, = 40 lb F2 = 30 lb dj = 20' – 0" dz = 10' – 0" A F2 = 30 lb F = 40 lb 8' – 0" 17' – 0" 3' – 0" 7'- 0" 5' – 0" A 10 ķips 3 kips/ft- 8' – 0" 8' – 0" 3'
Question 2 A truss tower is subjected to the following (unfactored) actions as shown in Figure 2. All supports are assumed to be pinned. Wind load: WL = 5kN Imposed load: IL = 20KN Dead load of the tower transferred to the left-leg: DL₁ = 25kN Dead load of the tower transferred to the right-leg: DLR = 25kN Dead load of the cantilever part (applied at the center of the cantilever pane): DLc = 10kN Calculate the factored design reactions of the foundations for the two legs (i.e., the maximum upward and downward reactions). WL WL WL DLL 1 DLC DLR All panes 4 m square Figure 2 ↓ IL
ANSWER TYPEWRITTEN FOR UPVOTE. SKIP IF YOU ALREADY DID THIS OR ELSE DOWNVOTE
A truss is detailed in the following Figure. For the given loading: (a) Identify null member(s) and null joint(s) (b) Determine the magnitude and nature of the axial forces in members DE, AD, GF, GB.
- Determine the force in member GH and state if the member is in tension or compression. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. FGH = Submit Part B. FBC= μA Value Part C Request Answer Determine the force in member BC and state if the member is in tension or compression. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. HA Value Submit Request Answer 3 μA Units FBG = Value → Units ? Determine the force in member BG and state if the member is in tension or compression. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. Units ? ?
Problem 4 Determine the force in each member of the truss shown below. 8 kN 4 kN 4 kN 4 kN 4 kN 4 kN - 4 kN 3.5 m B D E F 6@4 m = 24 m-