(Figure 1) shows a 3.0-cm-diameter solenoid passing through the center of a 6.2-cm-diameter loop. The magnetic field inside the solenoid is 0.16 T. Figure H Solenoid 60⁰ < 1 of 1 > What is the magnetic flux through the loop when it is perpendicular to the solenoid? Express your answer with the appropriate units. ▸ View Available Hint(s) 1.1×104 Wb Submit Previous Answers ✓ Correct Correct answer is shown. Your answer 11.31-10- Wb was either rounded differently or used a different number of significant figures than required for this part. Important: If you use this answer in later parts, use the full unrounded value in your calculations. MODEL: Consider the solenoid to be long so the field is constant inside and zero outside. SOLVE: The field is constant inside the solenoid. Take A to point in the same direction as the field. The magnetic flux is $ = Aloop Bloop = Asol · Bsol = ²Bsol Cos 0 = (1.5 × 10-² m)² (0.16 T) = 1.1 x 10-4 Wb Part B What is the magnetic flux through the loop when it is tilted at a 60° angle? Express your answer with the appropriate units. ▸ View Available Hint(s) μÅ S *= 5.65.10-5 ! → C Wb PWC ?

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Chapter1: Units, Trigonometry. And Vectors
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(Figure 1) shows a 3.0-cm-diameter solenoid passing through the center of
a 6.2-cm-diameter loop. The magnetic field inside the solenoid is 0.16 T
Figure
H
Solenoid
60°
1 of 1 >
What is the magnetic flux through the loop when it is perpendicular to the solenoid?
Express your answer with the appropriate units.
► View Available Hint(s)
= 1.1x10-4 Wb
Submit
Previous Answers
✓ Correct
Correct answer is shown. Your answer 11.31-10-5 Wb was either rounded differently or used a different number of significant figures than required for this part.
Important: If you use this answer in later parts, use the full unrounded value in your calculations.
MODEL: Consider the solenoid to be long so the field is constant inside and zero outside.
SOLVE: The field is constant inside the solenoid. Take A to point in the same direction as the field. The magnetic flux is
$ = Aloop - Bloop = Asol · Bsol = 77²Bsol cos 0 = π(1.5 × 10-² m)² (0.16 T) = 1.1 × 10-4 Wb
Part B
What is the magnetic flux through the loop when it is tilted at a 60° angle?
Express your answer with the appropriate units.
► View Available Hint(s)
HÅ
Þ5.65 10
●
+
-5
Wb
B
?
Transcribed Image Text:(Figure 1) shows a 3.0-cm-diameter solenoid passing through the center of a 6.2-cm-diameter loop. The magnetic field inside the solenoid is 0.16 T Figure H Solenoid 60° 1 of 1 > What is the magnetic flux through the loop when it is perpendicular to the solenoid? Express your answer with the appropriate units. ► View Available Hint(s) = 1.1x10-4 Wb Submit Previous Answers ✓ Correct Correct answer is shown. Your answer 11.31-10-5 Wb was either rounded differently or used a different number of significant figures than required for this part. Important: If you use this answer in later parts, use the full unrounded value in your calculations. MODEL: Consider the solenoid to be long so the field is constant inside and zero outside. SOLVE: The field is constant inside the solenoid. Take A to point in the same direction as the field. The magnetic flux is $ = Aloop - Bloop = Asol · Bsol = 77²Bsol cos 0 = π(1.5 × 10-² m)² (0.16 T) = 1.1 × 10-4 Wb Part B What is the magnetic flux through the loop when it is tilted at a 60° angle? Express your answer with the appropriate units. ► View Available Hint(s) HÅ Þ5.65 10 ● + -5 Wb B ?
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