Fig. 5.27 Two blocks A and B weighing 15 kN, and 3 kN respectively, are held in position against an applying a horizontal force P as shown in Fig. 5.27. Find the least value of P inclined plane by which will induce motion of the block A upwards. Angle of friction for all contact surfaces is 12º. [Ans. 14.025 kN]
Fig. 5.27 Two blocks A and B weighing 15 kN, and 3 kN respectively, are held in position against an applying a horizontal force P as shown in Fig. 5.27. Find the least value of P inclined plane by which will induce motion of the block A upwards. Angle of friction for all contact surfaces is 12º. [Ans. 14.025 kN]
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
Question 7
![Determine the force P required to start the wedge as shown in Fig. 5.26. The angle of friction for
all surfaces of contact is 15°.
Ans. 26.678 kN)
75%
P
P
The
100 kN
5.25
the same for both floor and wall.
sliding impends when 0 = 45°, determine the coeffi-
and they rest against vertical and horizontal
(Ans. 0.414)
1
B
C
2.5 kN
720
120
5°
P-
5°
Fig. 5.26
Fig. 5.27
7. Two blocks A and B weighing 15 kN, and 3 kN respectively, are held in position against an
inclined plane by applying a horizontal force P as shown in Fig. 5.27. Find the least value of
which will induce motion of the block A upwards. Angle of friction for all contact surfaces is 12º.
[Ans. 14.025 kN]
"J
T
B
In Fig. 5.28, C is a stone block weighing 6 kN. It is being raised slightly by means of two wooden
wedges A and B with a force P on wedge B: The angle between the contacting surfaces of the
wedge is 5°. If coefficient of friction is 0.3 for all contacting surfaces, compute the value of P
required to impend upward motion of the block C. Neglect weight of the wedges.
[Ans. 2.344 kN]
B
20
15°
10⁰
^
75°
TT
150
-P
CHAPTER 5
IA
Twelve Apostles](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa743490a-b6f9-4c78-b732-f5108271f497%2F08a12488-c753-480b-82c1-adc92f6e9e48%2Fp4w3qm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Determine the force P required to start the wedge as shown in Fig. 5.26. The angle of friction for
all surfaces of contact is 15°.
Ans. 26.678 kN)
75%
P
P
The
100 kN
5.25
the same for both floor and wall.
sliding impends when 0 = 45°, determine the coeffi-
and they rest against vertical and horizontal
(Ans. 0.414)
1
B
C
2.5 kN
720
120
5°
P-
5°
Fig. 5.26
Fig. 5.27
7. Two blocks A and B weighing 15 kN, and 3 kN respectively, are held in position against an
inclined plane by applying a horizontal force P as shown in Fig. 5.27. Find the least value of
which will induce motion of the block A upwards. Angle of friction for all contact surfaces is 12º.
[Ans. 14.025 kN]
"J
T
B
In Fig. 5.28, C is a stone block weighing 6 kN. It is being raised slightly by means of two wooden
wedges A and B with a force P on wedge B: The angle between the contacting surfaces of the
wedge is 5°. If coefficient of friction is 0.3 for all contacting surfaces, compute the value of P
required to impend upward motion of the block C. Neglect weight of the wedges.
[Ans. 2.344 kN]
B
20
15°
10⁰
^
75°
TT
150
-P
CHAPTER 5
IA
Twelve Apostles
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