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Fig. 5.27 Two blocks A and B weighing 15 kN, and 3 kN respectively, are held in position against an applying a horizontal force P as shown in Fig. 5.27. Find the least value of P inclined plane by which will induce motion of the block A upwards. Angle of friction for all contact surfaces is 12º. [Ans. 14.025 kN]

Fig. 5.27 Two blocks A and B weighing 15 kN, and 3 kN respectively, are held in position against an applying a horizontal force P as shown in Fig. 5.27. Find the least value of P inclined plane by which will induce motion of the block A upwards. Angle of friction for all contact surfaces is 12º. [Ans. 14.025 kN]

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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Determine the force P required to start the wedge as shown in Fig. 5.26. The angle of friction for all surfaces of contact is 15°. Ans. 26.678 kN) 75% P P The 100 kN 5.25 the same for both floor and wall. sliding impends when 0 = 45°, determine the coeffi- and they rest against vertical and horizontal (Ans. 0.414) 1 B C 2.5 kN 720 120 5° P- 5° Fig. 5.26 Fig. 5.27 7. Two blocks A and B weighing 15 kN, and 3 kN respectively, are held in position against an inclined plane by applying a horizontal force P as shown in Fig. 5.27. Find the least value of which will induce motion of the block A upwards. Angle of friction for all contact surfaces is 12º. [Ans. 14.025 kN] "J T B In Fig. 5.28, C is a stone block weighing 6 kN. It is being raised slightly by means of two wooden wedges A and B with a force P on wedge B: The angle between the contacting surfaces of the wedge is 5°. If coefficient of friction is 0.3 for all contacting surfaces, compute the value of P required to impend upward motion of the block C. Neglect weight of the wedges. [Ans. 2.344 kN] B 20 15° 10⁰ ^ 75° TT 150 -P CHAPTER 5 IA Twelve Apostles
Transcribed Image Text:Determine the force P required to start the wedge as shown in Fig. 5.26. The angle of friction for all surfaces of contact is 15°. Ans. 26.678 kN) 75% P P The 100 kN 5.25 the same for both floor and wall. sliding impends when 0 = 45°, determine the coeffi- and they rest against vertical and horizontal (Ans. 0.414) 1 B C 2.5 kN 720 120 5° P- 5° Fig. 5.26 Fig. 5.27 7. Two blocks A and B weighing 15 kN, and 3 kN respectively, are held in position against an inclined plane by applying a horizontal force P as shown in Fig. 5.27. Find the least value of which will induce motion of the block A upwards. Angle of friction for all contact surfaces is 12º. [Ans. 14.025 kN] "J T B In Fig. 5.28, C is a stone block weighing 6 kN. It is being raised slightly by means of two wooden wedges A and B with a force P on wedge B: The angle between the contacting surfaces of the wedge is 5°. If coefficient of friction is 0.3 for all contacting surfaces, compute the value of P required to impend upward motion of the block C. Neglect weight of the wedges. [Ans. 2.344 kN] B 20 15° 10⁰ ^ 75° TT 150 -P CHAPTER 5 IA Twelve Apostles
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