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Fig. 3-17 Applying Thevenin’s Theorem 1 ΚΩ + 80 Μ 2 ΚΩ +51 § 2 ΚΩ 1 ΚΩ (b) (a) Α 2 ΚΩ 1 ΚΩ +55 2 ΚΩ 1 ΚΩ 1 ΚΩ (c) 2 ΚΩ A + Vth Ο Β 3 ΚΩ R₁

Fig. 3-17 Applying Thevenin’s Theorem 1 ΚΩ + 80 Μ 2 ΚΩ +51 § 2 ΚΩ 1 ΚΩ (b) (a) Α 2 ΚΩ 1 ΚΩ +55 2 ΚΩ 1 ΚΩ 1 ΚΩ (c) 2 ΚΩ A + Vth Ο Β 3 ΚΩ R₁

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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How did this image get from example (a) to example (b)

**Figure 3-17: Applying Thevenin’s Theorem** This figure demonstrates the application of Thevenin’s Theorem through three circuit diagrams: (a), (b), and (c). **(a) Original Circuit:** - The circuit is powered by an 80 V voltage source. - Resistors are arranged in a combination of series and parallel: - Two 2 kΩ resistors in series with a 1 kΩ resistor across them. - Another three 2 kΩ resistors and 1 kΩ resistor in series. - The overall arrangement forms two main paths from the voltage source to the output terminals A and B. - Thevenin voltage (Vth) is represented at the terminals A and B after they are open-circuited. **(b) Simplified Thevenin Equivalent Without Load:** - This diagram shows a Thevenin equivalent circuit with a 5 V voltage source. - A single 1 kΩ resistor is placed in series between terminals A and B. - There is no load connected in this configuration. **(c) Thevenin Equivalent with Load:** - The diagram includes the same 5 V voltage source and 1 kΩ resistor from part (b). - However, a load resistor (R_L) of 3 kΩ is connected between terminals A and B. - The current flow (I) through the circuit is indicated. This illustration helps visualize the process of replacing a complex circuit with a simplified Thevenin equivalent circuit to analyze load behavior.
Transcribed Image Text:**Figure 3-17: Applying Thevenin’s Theorem** This figure demonstrates the application of Thevenin’s Theorem through three circuit diagrams: (a), (b), and (c). **(a) Original Circuit:** - The circuit is powered by an 80 V voltage source. - Resistors are arranged in a combination of series and parallel: - Two 2 kΩ resistors in series with a 1 kΩ resistor across them. - Another three 2 kΩ resistors and 1 kΩ resistor in series. - The overall arrangement forms two main paths from the voltage source to the output terminals A and B. - Thevenin voltage (Vth) is represented at the terminals A and B after they are open-circuited. **(b) Simplified Thevenin Equivalent Without Load:** - This diagram shows a Thevenin equivalent circuit with a 5 V voltage source. - A single 1 kΩ resistor is placed in series between terminals A and B. - There is no load connected in this configuration. **(c) Thevenin Equivalent with Load:** - The diagram includes the same 5 V voltage source and 1 kΩ resistor from part (b). - However, a load resistor (R_L) of 3 kΩ is connected between terminals A and B. - The current flow (I) through the circuit is indicated. This illustration helps visualize the process of replacing a complex circuit with a simplified Thevenin equivalent circuit to analyze load behavior.
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