[FESCN2+]eq [Fe3+]eq[SCN-]eq (Eqn. 2.8) Kea = . [Fe3+];: Calculate initial concentration of Fe3+ based on the dilution that results from adding KSCN solution and water to the original 0.0020 M Ee(NO3)3 solution. See Step 2 of the procedure for the volume of each substance used in Trials 1-4. Recall that in order to determine the concentration of ample that is a dilution of a solution with known concentration, we use M;V; = M;V;. (mL Fe(NO,);) · (0.0020M) [Fe3+]; total mL . Calculate the initial concentration of SCN, based on its dilution by Ee(NO3)3 and water: (mL KSCN) · (0.0020M) [SCN¯]; total mL

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Chapter1: Chemical Foundations
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can you show how i would set these up and solve them , use any fake data you want since i dont have the data , i just need to know what data i would need to collect and how to solve them ,thank you 

[FESCN2+]eq
[Fe3+]eq[SCN-]eq
Keq
(Eqn. 2.8)
1. [Fe3+]; : Calculate initial concentration of Fe3+ based on the dilution that results from adding KSCN
solution and water to the original 0.0020 M Ee(NO3)3 solution. See Step 2 of the procedure for the
volume of each substance used in Trials 1-4. Recall that in order to determine the concentration of
ample that is a dilution of a solution with known concentration, we use M;V; = M;V;.
[Fe3*]:
(mL Fe (NO3)3) · (0.0020M)
total mL
2. Calculate the initial concentration of SCN, based on its dilution by Ee(NO3)3 and water:
(mL KSCN) · (0.0020M)
[SCN-]; =
total ml
Transcribed Image Text:[FESCN2+]eq [Fe3+]eq[SCN-]eq Keq (Eqn. 2.8) 1. [Fe3+]; : Calculate initial concentration of Fe3+ based on the dilution that results from adding KSCN solution and water to the original 0.0020 M Ee(NO3)3 solution. See Step 2 of the procedure for the volume of each substance used in Trials 1-4. Recall that in order to determine the concentration of ample that is a dilution of a solution with known concentration, we use M;V; = M;V;. [Fe3*]: (mL Fe (NO3)3) · (0.0020M) total mL 2. Calculate the initial concentration of SCN, based on its dilution by Ee(NO3)3 and water: (mL KSCN) · (0.0020M) [SCN-]; = total ml
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