Federal regulations set an upper limit of 50 parts per million (ppm) of NH3 in the air in a work environment [that is, 50 molecules of NH3(g) for every million molecules in the air]. Air from a manufacturing operation was drawn through a solution containing 1.00 x 102 mL of 0.0105 M HCI. The NH3 reacts with HCl according to: NH3(aq) + HCI(aq) NH4CI(aq) After drawing air through the acid solution for 10.0 min at a rate of 10.0 L/min, the acid was titrated. The remaining acid needed 13.1 mL of 0.0588 M NaOH to reach the equivalence point. (a) How many grams of NH3 were drawn into the acid solution? (b) How many ppm of NH3 were in the air? (Air has a density of 1.20 g/L and an average molar mass of 29.0 g/mol under the conditions of the experiment.) (c) Is this manufacturer in compliance with regulations?

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4.115 Federal regulations set an upper limit of 50 parts per million
(ppm) of NH3 in the air in a work environment [that is, 50
molecules of NH3(8) for every million molecules in the air].
Air from a manufacturing operation was drawn through a
solution containing 1.00 x 102 mL of 0.0105 M HCI. The
NH3 reacts with HCl according to:
NH3(aq) + HCl(aq) ·
NH,CI(aq)
After drawing air through the acid solution for 10.0 min at a
rate of 10.0 L/min, the acid was titrated. The remaining acid
needed 13.1 mL of 0.0588 M NaOH to reach the equivalence
point. (a) How many grams of NH3 were drawn into the
acid solution? (b) How many ppm of NH3 were in the air?
(Air has a density of 1.20 g/L and an average molar mass of
29.0 g/mol under the conditions of the experiment.) (c) Is
this manufacturer in compliance with regulations?
Transcribed Image Text:4.115 Federal regulations set an upper limit of 50 parts per million (ppm) of NH3 in the air in a work environment [that is, 50 molecules of NH3(8) for every million molecules in the air]. Air from a manufacturing operation was drawn through a solution containing 1.00 x 102 mL of 0.0105 M HCI. The NH3 reacts with HCl according to: NH3(aq) + HCl(aq) · NH,CI(aq) After drawing air through the acid solution for 10.0 min at a rate of 10.0 L/min, the acid was titrated. The remaining acid needed 13.1 mL of 0.0588 M NaOH to reach the equivalence point. (a) How many grams of NH3 were drawn into the acid solution? (b) How many ppm of NH3 were in the air? (Air has a density of 1.20 g/L and an average molar mass of 29.0 g/mol under the conditions of the experiment.) (c) Is this manufacturer in compliance with regulations?
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