FeCl2•4H20(aq) + H2C2O4(aq)→ Fe C204 • 2H2O(s) +2H2O(/) + 2HCI(aq) A sample of FeCl2 • 4H2O with mass equal to 3.76 g of reacts with an excess of oxalic acid to form 2.88 g of Fe C204 • 2H2O is produced. Calculate the percent yield of the product. Use the following molar masses: FeCl2 • 4H2O -198.81g/mol Fe C204• 2H20 - 179.89 g/mol.
FeCl2•4H20(aq) + H2C2O4(aq)→ Fe C204 • 2H2O(s) +2H2O(/) + 2HCI(aq) A sample of FeCl2 • 4H2O with mass equal to 3.76 g of reacts with an excess of oxalic acid to form 2.88 g of Fe C204 • 2H2O is produced. Calculate the percent yield of the product. Use the following molar masses: FeCl2 • 4H2O -198.81g/mol Fe C204• 2H20 - 179.89 g/mol.
Chemistry
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Chapter1: Chemical Foundations
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
Transcribed Image Text:FeCl,•4H20(aq) + H2C2O4(aq) -
Fe C204 • 2H2O(s) +2H2O(/) + 2HCI(aq)
A sample of FeCl2• 4H2O with mass equal to 3.76 g of reacts with an excess of
oxalic acid to form 2.88 g of Fe C204 • 2H2O is produced. Calculate the percent
yield of the product.
Use the following molar masses:
FeCl2 • 4H20 -198.81g/mol
Fe C204 • 2H20 - 179.89 g/mol.
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