Fe2O36) + 2 Als) -» Al2O36) + 2 Fe) 159.70 26.98 101.96 55.85 Molar masses in g/mol 40. g of iron (III) oxide are combined with 12.5 g of aluminum how many grams of molten iron are prmed? D 18 g O 47 g
Fe2O36) + 2 Als) -» Al2O36) + 2 Fe) 159.70 26.98 101.96 55.85 Molar masses in g/mol 40. g of iron (III) oxide are combined with 12.5 g of aluminum how many grams of molten iron are prmed? D 18 g O 47 g
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![### Chemical Reaction Problem
**Balanced Reaction Equation:**
\[ \text{Fe}_2\text{O}_3(s) + 2 \text{Al}(s) \rightarrow \text{Al}_2\text{O}_3(s) + 2 \text{Fe}(l) \]
**Molar Masses in g/mol:**
- Fe\(_2\)O\(_3\): 159.70
- Al: 26.98
- Al\(_2\)O\(_3\): 101.96
- Fe: 55.85
**Problem Statement:**
Calculate the grams of molten iron formed when 40.0 g of iron (III) oxide is combined with 12.5 g of aluminum.
**Options:**
- 18 g
- 47 g
- 28 g
- 26 g
**Conclusion:**
Based on stoichiometry, identify the correct mass of iron produced.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2263fb78-830e-4ada-b34c-c6f0b1165c43%2Fd89d07a5-27ea-4f9a-a09b-ee6a634fc136%2F8p4b3tp_processed.png&w=3840&q=75)
Transcribed Image Text:### Chemical Reaction Problem
**Balanced Reaction Equation:**
\[ \text{Fe}_2\text{O}_3(s) + 2 \text{Al}(s) \rightarrow \text{Al}_2\text{O}_3(s) + 2 \text{Fe}(l) \]
**Molar Masses in g/mol:**
- Fe\(_2\)O\(_3\): 159.70
- Al: 26.98
- Al\(_2\)O\(_3\): 101.96
- Fe: 55.85
**Problem Statement:**
Calculate the grams of molten iron formed when 40.0 g of iron (III) oxide is combined with 12.5 g of aluminum.
**Options:**
- 18 g
- 47 g
- 28 g
- 26 g
**Conclusion:**
Based on stoichiometry, identify the correct mass of iron produced.
Expert Solution
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Step 1
The given data:
The mass of iron(III) oxide = 40 g
The mass of aluminum = 12.5 g
To determine = The mass of molten iron formed.
Step by step
Solved in 5 steps
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