How do I solve for 90% confidence interval fAind a salunon onyourownmemorization of1ne solution14.indpevelm> problemsokvingM-10.50M- 6016dipendents neihod hingusedSS-108SS-116a.is there a sighifiant differchce in performance on newprobeims for tnese two groups?use a two-tauled testwith a-005Mli-ll2-0Null hypoiness - Ho:Aetermatire hypacers>Hii lli -elz+0df-81df=7 O poolld variance s*p = SSi+SSz = 108+ 116224 1614dfi tdf2717e estimatedstandard error SIMI -M2) =SP+S?P16 1632-14-2Ot-stats> t= (MI-M2)+Cli -lUz)S(Mi-M2)10.5-6.16 40342.172.find the crihal valuef%=8+8-2=1420145-criticalvalueThe t-stat vasue is mgher than the criticaevalue,turcrore wemust reject the hull nypoIhes1s .In conceusion. tRere is a signafica nt diffeichce in pertarmance on new problimsfor the girengroupsbconstruct a 907• Con fidence intervae to cS TImate the size Of themeandifferenceCTl, -lz= Mi-Mz± tS (MI-M2)0 = 10.5-6. 16 2.17 (2)나.3나 4.3나(8.681 0)

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Description: How do I solve for 90% confidence interval fAind a salunon onyourownmemorization of1ne solution14.indpevelm> problemsokvingM-10.50M- 6016dipendents neihod hingusedSS-108SS-116a.is there a sighifiant differchce in performance on newprobeims for tnese

The level of significance is α=1-0.9=0.1 The 90% confidence interval is…

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fAnd a salunan onyCUrawb memorization of1le salution indipevelmm> ploblem solving dipendem meihod hin M-10-50 M- 6 16 SS-108 SS-116 used a.is there a signifiant diffeichce in performance on new prabeims for these TWO groupse Use a two-tauled rest with a-.05 Null hypotnesas- Hoi lli-llz-0 Altematire hypanis>Hii lli-elz#0 poolld variance→ S*P = SSi+SSz = 224- 16 14 %3D 108+ 116 %3D afi tdfz 717 estimatedstandara error» S(MI - M2) =Sp+s?P 16 16 32-4=2 ni -Stats→ t= (MI-M2)+i-Uz) S(MI-M2) 10.5-6.16 4.34 -2.17 find the chraevalue cf=8+8-2%3D144 20145-criticaevalue The 1-stat vasue is mgher than the criticaevalue, turciore wemust reject ihe hull nypothls1s. In conclusion. thereis a sighifice nt dif Ferchce in perfarmanCI on new problems for thigirengroups aconstruct a 907• Confidlence inteIval to cs Timate the s1ze Of the meandifference CIl,-llz=MI-M21ts (MI-M2) 0 = 10:5-6.16 2.17 (2) 나.3나 4.3나 (8.681 0)

fAnd a salunan onyCUrawb memorization of1le salution indipevelmm> ploblem solving dipendem meihod hin M-10-50 M- 6 16 SS-108 SS-116 used a.is there a signifiant diffeichce in performance on new prabeims for these TWO groupse Use a two-tauled rest with a-.05 Null hypotnesas- Hoi lli-llz-0 Altematire hypanis>Hii lli-elz#0 poolld variance→ S*P = SSi+SSz = 224- 16 14 %3D 108+ 116 %3D afi tdfz 717 estimatedstandara error» S(MI - M2) =Sp+s?P 16 16 32-4=2 ni -Stats→ t= (MI-M2)+i-Uz) S(MI-M2) 10.5-6.16 4.34 -2.17 find the chraevalue cf=8+8-2%3D144 20145-criticaevalue The 1-stat vasue is mgher than the criticaevalue, turciore wemust reject ihe hull nypothls1s. In conclusion. thereis a sighifice nt dif Ferchce in perfarmanCI on new problems for thigirengroups aconstruct a 907• Confidlence inteIval to cs Timate the s1ze Of the meandifference CIl,-llz=MI-M21ts (MI-M2) 0 = 10:5-6.16 2.17 (2) 나.3나 4.3나 (8.681 0)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Contingency Table

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Question

How do I solve for 90% confidence interval

fAind a salunon onyourown
memorization of1ne solution
14.
indpevelm> problem
sokving
M-10.50
M- 6016
dipendents neihod hing
used
SS-108
SS-116
a.is there a sighifiant differchce in performance on newprobeims for tnese two groups?
use a two-tauled testwith a-005
Mli-ll2-0
Null hypoiness - Ho:
Aetermatire hypacers>Hii lli -elz+0
df-81
df=7 O poolld variance s*p = SSi+SSz = 108+ 116
224 16
14
dfi tdf2
717
e estimatedstandard error SIMI -M2) =SP+S?P
16 16
32-14-2
Ot-stats> t= (MI-M2)+Cli -lUz)
S(Mi-M2)
10.5-6.16 4034
2.17
2.
find the crihal value
f%=8+8-2=14
20145-criticalvalue
The t-stat vasue is mgher than the criticaevalue,
turcrore wemust reject the hull nypoIhes1s .
In conceusion. tRere is a signafica nt diffeichce in pertarmance on new problims
for the girengroups
bconstruct a 907• Con fidence intervae to cS TImate the size Of themeandifference
CTl, -lz= Mi-Mz± tS (MI-M2)
0 = 10.5-6. 16 2.17 (2)
나.3나 4.3나
(8.681 0)

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