**Title: Calculating the Moment through the Center of a Pipe Using a Wrench****Objective**: To determine the moment generated by a force applied using a wrench on a pipe.**Diagram Explanation**:The diagram illustrates a wrench exerting a force on a pipe. Key components and dimensions are labeled:1. **Wrench**: Positioned on the pipe at an angle.2. **Force (F)**: Applied force of 37 pounds (#), represented by an arrow pointing at an angle away from the wrench.3. **Dimensions**: - The distance along the wrench handle is 12 inches. - Vertical component of the distance is 8 inches. - Horizontal slider or handle extension is denoted as 15 inches, which is also a partial diagonal distance. - The total effective distance if perpendicular is 5 inches.**Problem Statement** (2.16):Calculate the moment through the center of the pipe due to the force exerted by the wrench.The task involves determining the moment, which is the rotational equivalent of linear force, generated about a specified point—in this case, the center of the pipe—by the applied force. This involves understanding vectors and applying principles of mechanics to resolve the force into its components and calculate the resulting moment.

Given:- The magnitude of the force exerted by the wrench = F = 39# The length of the wrench is 17" To determine:- The moment through the center of the pipe due to the forceA free-body diagram will be The angle θ will be tan θ=815θ=tan-1 0.533θ=28.07° Similarly, The angle ϕ will be tan ϕ=512ϕ=tan-1 0.4166ϕ=22.61° Therefore, The moment through the center of the pipe due to the force will be MA=-F×cos θ+ϕ×17MA=-39×cos 28.07+22.61×17MA=-420 #-inch Hence, The moment through the center of the pipe due to the force = 420 #-inch